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3 years ago

what would be the final volume when 2.20 M solution is made from 25.0 mL of a 12.0 M solution? plzz show work

Chemistry

1 answer:

cupoosta [38]3 years ago

7 0

Answer:

136.36 mL

Explanation:

Here we have to use the dilution formula

From C1V1= C2V2

Where;

C1= initial concentration of the solution= 12.0 M

C2= final concentration of the solution= 2.20 M

V1 = initial volume of the solution= 25.0 ml

V2= final volume of the solution= ?????

Then recall;

C1V1=C2V2

V2 = C1V1/C2

Substituting values from the parameters given;

V2= 12.0 × 25.0 / 2.20

V2= 136.36 mL

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How many cobalt atoms are in 345 g of cobalt

lilavasa [31]

Answer:

$\boxed {\boxed {\sf About \ 3.53 \ *10^{24}atoms \ Co}}$

Explanation:

To convert from grams to atoms:

Convert grams to moles
Convert moles to grams

1. Convert grams to moles

First, find the molar mass of cobalt using the Periodic Table of Elements.

Cobalt (Co): 58.93319 g/mol

Next, use this mass as a ratio or fraction.

$\frac{58.93319 \ g\ Co}{1 \ mol \ Co}$

Multiply the mass of the given sample (345 grams) by this ratio.

$345 \ g \ Co *\frac{58.93319 \ g\ Co}{1 \ mol \ Co}$

Flip the fraction so the grams of Cobalt will cancel each other out when multiplying.

$345 \ g \ Co *\frac{1 \ mol \ Co}{58.93319 \ g\ Co}$

$345 \ *\frac{1 \ mol \ Co}{58.93319 }$

$\frac{345 \ mol \ Co}{58.93319 } =5.854086636 \ mol \ Co$

2. Convert moles to atoms

Use Avogadro's Number, which tells us the number of units (in this case atoms) in 1 mole.

$6.022 *10^{23} \ atoms/mol$

Use this number as a ratio or fraction.

$\frac{6.022 * 10^{23} \ atoms \ Co}{1 \ mol \ Co}}$

Multiply this ratio by the number of moles we found.

$5.854086636 \ mol \ Co*\frac{6.022 * 10^{23 }\ atoms \ Co}{1 \ mol \ Co}}$

The moles of Cobalt will cancel.

$5.854086636 \ *\frac{6.022 * 10^{23 }\ atoms \ Co}{1 }}$

$5.854086636 \ *{6.022 * 10^{23 }\ atoms \ Co}$

$3.52533097*10^{24} \ atoms \ Co$

3.Round

The original measurement of 345 has 3 significant figures (3, 4, and 5). We must round to 3 sig figs, which is the hundredth place for this measurement.

$3.52533097*10^{24} \ atoms \ Co$

The 5 in the thousandth place tells us to round the 2 to a 3.

$3.53 \ *10^{24}atoms \ Co$

There are about 3.53*10²⁴ atoms of cobalt in 345 grams.

6 0

3 years ago

1. Does the temperature rise or drop when you mix vinegar and baking soda.

Viktor [21]

Answer:

Yes

Explanation:

In a chemical reaction heat is produced as a result of the reaction

3 0

3 years ago

The mass of a jar of sugar is 11. 9 kg. What is the total mass of 13 jars of sugar?.

Masteriza [31]

Answer:

154.7

Explanation:

11.9kg x 13 = 154.7

5 0

2 years ago

A 25.0-mL sample containing Cu2+ gave an instrument signal of 25.2 units (corrected for a blank). When exactly 0.500 mL of 0.027

irga5000 [103]

Answer:

The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.

Explanation:

The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:

$C = \frac{n}{V} \\0.0275 = \frac{n}{0.0005} \\$

n = 1.375x10⁻⁵ mol

The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):

1.375x10⁻⁵ mol _________ 19.9 units

x _________ 25.2 units

x = 1.741x10⁻⁵mol

Finally, we can calculate the Cu²⁺ concentration :

C = 1.741x10⁻⁵mol / 0.025 L

C = 6.964x10⁻⁴ M

7 0

4 years ago

(Will give brainliest)

Elanso [62]

Answer:

Explanation:

Its chemical energy to Chemical energy because carbon is a chemical in science sorry if its incorrect.

4 0

3 years ago