Answer:
A. 8.4
Explanation:
[OH⁻] = 2.6 × 10⁻⁶ Take the negative log of each side
-log[OH⁻] = pOH = 5.59 Apply the pH/pOH relation
pH + pOH = 14.00 Insert the value of pOH
pH + 5.59 = 14.00 Subtract 5.59 from each side
pH = 14.00 -5.59 = 8.41
Answer:
0.96g of sodium hydride
Explanation:
Equation of reaction:
NaH + H20 = NaOH + H2
Mass of hydrogen gas produced (m) = PVM/RT
P = 765torr - 28torr = 737torr = 737/760 = 0.97atm, V = 982mL = 982cm^3, M = 2g/mol, R = 82.057cm^3.atm/gmol.K, T = 28°C = 28 + 273K = 301K
m = (0.97×982×2)/(82.057×301) = 0.08g of hydrogen gas
From the equation of reaction
1 mole (24g) of sodium hydride produced 1 mole (2g) of hydrogen gas
0.08g of hydrogen gas would be produced by (24×0.08)/2 = 0.96g of sodium hydride
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Answer: 166.023×1023
Explanation:
Mass of 6.023×1023 atoms of oxygen = gram atomic mass of oxygen.
Mass of 6.023×1023 atoms of oxygen = 16g
∴ Mass of 1 atom of oxygen =166.023×1023
Answer:
2.6×10^-19 J/photon
Explanation:
E of photon = h × ν
where h= 6.63 × 10^-34 j.s
v= C ÷ λ
E = ( h × c) ÷ λ
E = (6.63 × 10^-34 × 3.00
×10^8 ) ÷ ( 765 × 10^-9)
E = 2.6×10^-19 J/photon
