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GenaCL600 [577]
4 years ago
8

Solve. 4n+3−n=71+5n what does n equal?

Mathematics
2 answers:
Valentin [98]4 years ago
8 0

Answer:

No solution

Step-by-step explanation:

5n+3=71+5n

3=71

No solution

nikklg [1K]4 years ago
7 0

<em>So</em><em> </em><em>n</em><em> </em><em>equals</em><em> </em><em>-</em><em>3</em><em>4</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

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otez555 [7]
1 gallon is 4 quarts. So if 1 gallon is 6 pounds, than a fourth of 6 pounds is the weight of a quart.
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Answer:
1 quart of unleaded gasoline = 24 ounces
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3 years ago
Kiran is flying a kite. He gets tired, so he stakes the kite into the ground. The kite is on a string that is 12 feet long and m
Nataly [62]

Answer:

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3 years ago
Acute △ABC with angles α, β, and γ is inscribed in a circle. Tangents to the circle at points A, B, and C intersect in points M,
SOVA2 [1]

Answer:

The measures of angles of triangle MNP are

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

step 1

Find the measure of arcs AB, BC and AC

we know that

The inscribed angle is half that of the arc it comprises.

so

\gamma=\frac{1}{2}[arc\ AB] ----> arc\ AB=2\gamma\\\alpha=\frac{1}{2}[arc\ BC] ----> arc\ BC=2\alpha\\\beta=\frac{1}{2}[arc\ AC] ----> arc\ AC=2\beta

step 2

Find the measure of angle M

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

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substitute

M=\frac{1}{2}[2\gamma+2\alpha-2\beta]\\M=[\gamma+\alpha-\beta]

step 3   

Find the measure of angle N

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

N=\frac{1}{2}[arc\ AC+arc\ BC-arc\ AB]

substitute

N=\frac{1}{2}[2\beta+2\alpha-2\gamma]\\N=[\beta+\alpha-\gamma]

step 4    

Find the measure of angle P

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

P=\frac{1}{2}[arc\ AC+arc\ AB-arc\ BC]

substitute

P=\frac{1}{2}[2\beta+2\gamma-2\alpha]\\P=[\beta+\gamma-\alpha]

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4 years ago
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IRISSAK [1]

Answer:

A ∩ B = {4, 6}

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