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jolli1 [7]
3 years ago
14

Factor completely and then place the factors in the proper location on the grid. 8y 2 + 6y + 1

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
4 0

Answer:

Factored form the given quadratic equation 8y^2+6y+1 is  (2y+1)(4y+1)

Step-by-step explanation:

Given : 8y^2+6y+1

We  have to factorize the given equation completely and place the factors in the proper location on the grid.

Consider the given quadratic equation 8y^2+6y+1.

We solve the given quadratic equation using middle term splitting method,

6y can be written as 4y + 2y , then equation becomes,

8y^2+6y+1=8y^2+4y+2y+1

Taking 4y common from first two term and 1 common from last two term , we have,

\Rightarrow 4y(2y+1)+1(2y+1)

\Rightarrow (2y+1)(4y+1)

Thus, factored form the given quadratic equation 8y^2+6y+1 is  (2y+1)(4y+1)

The placement of the factors in the proper location on the grid is shown in figure attached below.

kkurt [141]3 years ago
3 0
(2y + 1)(4y + 1)
 Hope this helps
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<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.


The complete question is:

Which pair of statements describe the end behavior of the graph of the function f(x) = x³ + 2x² − 5x − 6?

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D.) As x approaches negative infinity, f(x) approaches negative infinity. As x approaches infinity, f(x) approaches infinity.

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