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user100 [1]
3 years ago
7

Ron is planning for the back-to-school rush at his store. Last year he estimated that he would need 168 notebooks, but he sold 2

00 notebooks. What was the percent error of Ron’s estimate?
Mathematics
2 answers:
lakkis [162]3 years ago
6 0
I) 30 × 4 + (x - 30) × 5 < 200 

<span>(II) 20 × 4 + (x - 20) × 5 > 200 </span>


<span>Restated: </span>

<span>(I) 120 + 5x - 150 < 200; 5x < 230 </span>

<span>(II) 80 + 5x - 100 > 200; 5x > 220 </span>

<span>220 < 5x < 230 </span>
<span>44 < x < 46 </span>

<span>There are exactly 45 students in the class.</span>
IgorC [24]3 years ago
6 0

Answer:

Percentage error of Ron’s estimate is 16%.

Step-by-step explanation:

Formula

Percentage\ error = \frac{Change\ in\ value\times 100}{Exact\ value}

Where

Change in value = |Approx value - Exact value|

As given

Ron is planning for the back-to-school rush at his store.

Last year he estimated that he would need 168 notebooks, but he sold 200 notebooks.

Approx value = 168

Exact value = 200

Thus

Change in value = |168 - 200|

Change in value = |32|

Change in value = 32

Put all the values in the formula

Percentage\ error = \frac{32\times 100}{200}

Percentage\ error = \frac{3200}{200}

Percentage\ error = \frac{32}{2}

Percentage error = 16%

Therefore the percentage error of Ron’s estimate is 16%.

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pav-90 [236]

Answer:

Yes it is

Step-by-step explanation:

when you add up all parts of a triangle they are equal to 180

6 0
3 years ago
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Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p
zubka84 [21]

Answer:  The required answers are

(a) 0.25,    (b) 0.62,    (c) 6.

Step-by-step explanation:  Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.

(a) The probability of getting 5 heads is given by

P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.

(b) The probability of getting 5 or more than 5 heads is

P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0
3 years ago
Solve 7x − 2(x + 1) = 6x + 14.<br> −12<br> 12<br> −16<br> 16
Vladimir79 [104]
7x-2(x+1)=6x+14
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meriva
You have to find out what 15% of $78 dollars is.  If you have to do this in your head and not on a calculator you can find 10%, then cut that number in 1/2 and add it to the answer.  So 10% of $78 is 7.8 so $7.80.  You can divide 7.80 by 2 and get 3.9 and add that to 7.8 which is 11.70.  So 15% of $78 is $11.70. 
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