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user100 [1]
3 years ago
7

Ron is planning for the back-to-school rush at his store. Last year he estimated that he would need 168 notebooks, but he sold 2

00 notebooks. What was the percent error of Ron’s estimate?
Mathematics
2 answers:
lakkis [162]3 years ago
6 0
I) 30 × 4 + (x - 30) × 5 < 200 

<span>(II) 20 × 4 + (x - 20) × 5 > 200 </span>


<span>Restated: </span>

<span>(I) 120 + 5x - 150 < 200; 5x < 230 </span>

<span>(II) 80 + 5x - 100 > 200; 5x > 220 </span>

<span>220 < 5x < 230 </span>
<span>44 < x < 46 </span>

<span>There are exactly 45 students in the class.</span>
IgorC [24]3 years ago
6 0

Answer:

Percentage error of Ron’s estimate is 16%.

Step-by-step explanation:

Formula

Percentage\ error = \frac{Change\ in\ value\times 100}{Exact\ value}

Where

Change in value = |Approx value - Exact value|

As given

Ron is planning for the back-to-school rush at his store.

Last year he estimated that he would need 168 notebooks, but he sold 200 notebooks.

Approx value = 168

Exact value = 200

Thus

Change in value = |168 - 200|

Change in value = |32|

Change in value = 32

Put all the values in the formula

Percentage\ error = \frac{32\times 100}{200}

Percentage\ error = \frac{3200}{200}

Percentage\ error = \frac{32}{2}

Percentage error = 16%

Therefore the percentage error of Ron’s estimate is 16%.

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