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diamong [38]
3 years ago
12

the total resistance is an electrical circuit consisting of three heater elements is 14.7 ohms.the resistance of two heater elem

ents are 5.57 ohms and 4.91 ohms. find the resistance of the third heater element.
Mathematics
1 answer:
Ugo [173]3 years ago
5 0

We need to know whether all three are in series, all three are
in parallel, or one is in series with the parallel combination of
the other two.

If one is in series with the other two in parallel, then we need
to know the positions of the 5.57 ohms and the 4.91 ohms. 

The answer is different for each of those cases, and I'm not
about to sit here and work out all the possible answers, for
5 points.

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Adam wanted to play his video games. His mother told him that he needed to finish his homework, clean out the dishwasher, and cl
Deffense [45]

Answer:

148 minutes = 2h 28 min

Step-by-step explanation:

48min+(25+75mins)=48+100=148

5 0
2 years ago
Identify the quadrant in which each point is located.
kykrilka [37]

A) Quadrant 1

B) Quadrant 3

C) Quadrant 1

D) Quadrant 4

E) Quadrant 2

5 0
3 years ago
If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
6 0
3 years ago
Read 2 more answers
Given (21,7) and (x,<br> 1), find all x such that the distance between these two points is 17.
Dmitriy789 [7]

Answer:

21+/-sqrt(253)=x

So one value for x is 21+sqrt(253)

and another is 21-sqrt(253)

Problem:

Given (21,7) and (x,1), find all x such that the distance between these two points is 17.

Step-by-step explanation:

Change in x is x-21

Change in y is 7-1=6

distance^2=(change in x)^2+(change in y)^2

17^2=(x-21)^2+(6)^2

289=(x-21)^2+36

Subtract 36 on both sides:

289-36=(x-21)^2

253=(x-21)^2

Take square root of both sides:

+/-sqrt(253)=x-21

Add 21 on both sides:

21+/-sqrt(253)=x

6 0
3 years ago
Angela and Ryou are painting a room. Angela has 2/1/2 gallons of blue paint and Ryou has half as much white paint. It will take
mote1985 [20]
Blue paint - 2/1/2 = 1 gallon
White paint - 1/2 gallon
1 wall - 1/4 quart of paint
As 1 quart = 1/4 gallon, one gallon of paint is enough to cover 16 walls.
the walls can be either white or blue and the leftover will be 1  and 1/4 gallon paint.
3 0
3 years ago
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