Answer:
<h3>
A = ²⁵/₄x² + ⁷⁵/₂x + 50</h3>
Step-by-step explanation:
L = ⁵/₂x + 10
W = ⁵/₂x + 5
A = L•W
A = (⁵/₂x + 10)(⁵/₂x + 5)
A = ⁵/₂x•⁵/₂x + ⁵/₂x•5 + 10•⁵/₂x + 10•5
A = ²⁵/₄x² + ²⁵/₂x + ⁵⁰/₂x + 50
A = ²⁵/₄x² + ⁷⁵/₂x + 50
Or if yoy mean:
L = 5/(2x) + 10
W = 5/(2x) + 5
A = [5/(2x) + 10][5/(2x) + 5] = 25/(4x²) + 75/(2x) + 50
Answer:
1245
Step-by-step explanation:
Distribute the number 3 to each of the numbers in the second set of parentheses. Be careful to remember to add zeros to the number depending on which place holder the number is in.
Demonstration:
3 × 400
3 x 10
3 x 5
After solving each equation, add the total
1200 + 30 + 15 = 1245
Answer:
-5
Step-by-step explanation:
-7 - (-2)
-7 + 2
Example: If you owe someone $7, and you give them $2, how much do you still owe? You are owing him $7 so it's a negative and you give him $2 which is a negative as well since you are giving it to him. So, to answer how much do you still owe, you would add $2 to the $7 you owed, so now, you owe him $5, which is a negative since you OWE him.
Hope this helps:)
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
