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4 years ago

A dog has a mass of 19 kg. What is the mass of the dog in

Mathematics

1 answer:

liq [111]4 years ago

6 0

Answer:c. 1.9 × 10⁴ g

Step-by-step explanation:

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What is the decimal expansion of 7/22?

grigory [225]

It should be 0.3181818181818 so it would be a repeating decimal

8 0

3 years ago

Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was $43.25 He had to pay a $7 ent

Travka [436]

Answer:

the number of the minutes 29

Step-by-step explanation:

because the if we take the cost from the session it will be 36.25 and divide by 1.25 because it takes every minute 1.25 so it will be 29

6 0

3 years ago

Read 2 more answers

The differnce between two numbers is 33. Three times the smaller is equal to 5 more than larger. What are the numbers?

Liula [17]

The two numbers are <u>19 and 52.</u>

<h3>EXPLANATION</h3>

19 x 3 = 57, 57 - 5 = 52, 52 - 19 = 33.

Hope this helps!

7 0

3 years ago

Evaluate the piecewise function at the indicated values from the domain:

lidiya [134]

In this question, we given a piece-wise function, that has different definitions depending on the domain.

Evaluate the function at x = 0.

The exercise asks for us to evaluate the function at $x = 0$

We have to look at the definition, and see which definition includes $x = 0$ . The equal sign at $x = 0$ is on the second definition, that is:

$f(x) = 1, 0 \leq x < 2$

Thus, at $x = 0$ , the value of the function is 1, and the correct answer is given by option A.

For another example of evaluation of a piece-wise function, you can check brainly.com/question/17966003

7 0

3 years ago

Evaluate the function at the indicated values if possible. If an indicated value is not in the domain, say so.

goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

$f(x)=\frac{x+7}{x^2-9}$ is the given function.

We are asked to find:

$f(-7)$

$f(2)$

$f(3)$ .

f(-7) means to replace x in the expression called f with -7:

Evaluate $\frac{x+7}{x^2-9}$ at $x=-7$

$\frac{(-7)+7}{(-7)^2-9}$

$\frac{0}{49-9}$

$\frac{0}{40}$

$0$

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate $\frac{x+7}{x^2-9}$ at $x=2$

$\frac{2+7}{2^2-9}$

$\frac{9}{4-9}$

$\frac{9}{-5}$

$\frac{-9}{5}$

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate $\frac{x+7}{x^2-9}$ at $x=3$

$\frac{3+7}{3^2-9}$

$\frac{10}{9-9}$

$\frac{10}{0}$

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0

3 years ago