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dexar [7]
3 years ago
7

Please help..

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0
They are all on a graph. They all have an x and y in the calculations. The graph has an x and y axes
podryga [215]3 years ago
3 0

Answer:

Answer is in step-by-step.

Step-by-step explanation:

What do you noticed about each solution:

  • Straight lines? I honestly don't know.

What do you notice about the graphs for each set of equations:

  • They all intersect.

What do you notice about each set of equations:

  • They each have a negative and positive equation.

What generalization can you make:

  • If two equations are given, and the slope of one is positive while the other is negative, the lines will intersect.
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"A shipment has 20 items. Five items will be picked randomly and checked for quality. If at least one item is defective, then th
Thepotemich [5.8K]

Answer:

1 - \frac{(20-k)(19-k)(18-k)(17-k)(16-k)}{20*19*18*17*16}

Step-by-step explanation:

If k items out of 20 total items are defective, then the number of non-defective item is 20 – k. The probability of choosing 5 items where all of them are non-defective is

- For the 1st slot the chance is (20 – k)/20

- For the 2nd slot the chance is (20-k-1)/(20-1) = (19-k)/19

- For the 3rd slot: (18 – k)/18

- 4th : (17 – k)/17

- 5th: (16 – k)/16

The probability in total would be

\frac{(20-k)(19-k)(18-k)(17-k)(16-k)}{20*19*18*17*16}

So the probability of selecting at least 1 defective item is the inverse of this, which is

1 - \frac{(20- k)(19-k)(18-k)(17-k)(16-k)}{20*19*18*17*16}

4 0
3 years ago
LOOK AT PICTURE, THEN ANWSER, WHOEVER IS CORRECT I WILL MARK BRAINIEST:)
ASHA 777 [7]

Answer:

C

Step-by-step explanation:

It has to be either A or C because the function is decreasing as you move left to right, this only occurs when the number inside parenthesis is less than 1.

It isn't A because if you plug in x=0, the value is 2, but on the graph it is greater than 2.

pleae give thanks by hitting heart button :)

6 0
2 years ago
Read 2 more answers
Ill give brainliest pls help i am so stuck
jok3333 [9.3K]

Answer:

Part A:

Since the slopes of the lines are not equal, the pair of equations for lines A and B will have one solution.

Part B:

(3 ,5 ) is the solution to the equations of lines A and B.

Step-by-step explanation:

Part A:

We are required to determine the number of solutions that the pair of equations for lines A and B have. To do this, we shall determine the slope of each line;

A straight line labeled A joins the ordered pair 2, 6 with the ordered pair 6, 2. The slope is defined as;

(change in y) / (change in x)

The slope of line A is thus;

(2 - 6)/(6 - 2) = -1

A straight line B joins the ordered pair 0, 3 with the ordered pair 4.5, 6.

On the other hand, the slope of line B is;

(6 - 3) / (4.5 - 0) = 2/3

Since the slopes of the lines are not equal, the pair of equations for lines A and B will have one solution.

Part B:

What is the solution to the equations of lines A and B?

We first need to determine the equation of each line;

Line A, the slope was found to be -1 and the line passes through (2,6)

The equation of the line in slope intercept form is;

y = -x + c

6 = -2 + c

c = 8

y = -x + 8

On the other hand, the slope of line B was found to be 2/3 and the line passes through (0,3). Therefore, we have;

y = 2/3x + c

3 = 2/3 (0) + c

c= 3

y = (2/3)x + 3

The graph of these two lines is shown in the attachment below. The lines intersect at (3 ,5 ) which is the solution to the equations of lines A and B.

The graphical solution to a system of linear equations is given by the point of intersection of the two lines representing each equation.

3 0
3 years ago
Find the exact value of tan 150° in simplest form with a rational<br> denominator.
Ainat [17]

Step-by-step explanation:

tan150°

= -tan30°

= -√3/3.

7 0
2 years ago
Order from greatest to least<br> 5 1/2, 5.05, 5 5/9<br> 37/10, 3 2/5, 3 1/4<br> 5/7, 5/6, 5/12
bonufazy [111]
3 2/8, 5/7, 5/6 5/12

Greatest to least: 5 5/9, 5 1/2, 5.05, 37/10, 3 4/10, 3 1/4, 5/6, 5/7, 5/12.
7 0
2 years ago
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