Answer:
if you scored a 83 on every test in a class your standard deviation would be 0. The point is that the bigger the standard deviation the more "variation" you will find in the raw numbers.... "D" (international equities) is the answer to this question...
it has the highest percent for the standard deviation, this it is the
MOST IN-COSISTENT
Step-by-step explanation:
Answer: The first one
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
2/1=2, 8/4=2, 12/6=2
Answer:
Hope this helps :-)
Step-by-step explanation:
<h3>
I don't know which one it is, but the answer to the one in the picture is </h3><h2>
4b+14</h2><h3>
and the answer to the one on brainly is </h3><h2>
2b-3</h2>
To solve this we are going to use the future value of annuity ordinary formula:
![FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3DP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bkt%7D%20-1%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
where

is the future value

is the periodic payment

is the interest rate in decimal form

is the number of times the interest is compounded per year

is the number of payments per year

is the number of years
We know for our problem that

and

. To convert the interest rate to decimal form, we are going to divide the rate by 100%:

Since the deposit is made semiannually, it is made 2 times per year, so

.
Since the type of the annuity is ordinary, payments are made at the end of each period, and we know that we have 2 periods, so

.
Lets replace the values in our formula:
![FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3DP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bkt%7D%20-1%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
![FV=6200[ \frac{(1+ \frac{0.06}{2} )^{(2)(5)} -1}{ \frac{0.06}{2} } ]](https://tex.z-dn.net/?f=FV%3D6200%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7B0.06%7D%7B2%7D%20%29%5E%7B%282%29%285%29%7D%20-1%7D%7B%20%5Cfrac%7B0.06%7D%7B2%7D%20%7D%20%5D)
We can conclude that the correct answer is <span>
$71,076.06</span>