Sorry that is wrong, you distribute the 2 to the h and the 8 so it would be 2h-16-h. that would be h-16 on the left side,
- the probability that a person has the virus given that they have tested positive is 0.0151.
- the probability that a person does not have the virus given that they have tested negative is 0.9999
P(A) = 1/600 = 0.0017
P(B) = 0.9 * 0.0017 + 0.1 * (1 - 0.0017) = 0.1014
A) P (has the virus | tested positive) = P (tested positive | has the virus) ×
P (has the virus)/ P (tested positive)
= 0.9 × 0.0017/0.1014
= 0.0151
B) P (does not have the virus | tested negative) = P (tested negative | does not have the virus) × P (does not have the virus)/ P (tested negative)
= (1 - 0.1) *× (1 - 0.0017)/ (1 - 0.1014)
= 0.9999
Probability is the department of mathematics regarding numerical descriptions of ways likely an occasion is to occur, or how possibly it's far that a proposition is genuine. The possibility of an occasion varies between zero and 1, wherein, roughly speaking, 0 suggests the impossibility of the occasion and 1 shows certainty. The better the possibility of an event, the more likely it is that the event will arise.
A simple instance is the tossing of an honest (unbiased) coin. since the coin is truthful, the 2 results ("heads" and "tails") are both equally likely; the possibility of "heads" equals the chance of "tails"; and considering the fact that no different results are feasible, the possibility of both "heads" or "tails" is 1/2 (that could additionally be written as 0.5 or 50%).
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Answer:
It is 26cm.
Step-by-step explanation:
Do Pythagorean theorem, a^2+b^2=c^2
So 24^2+10^2,
576+100,
676.
Next, we square root it to simplify c^2 to get c by itself
(sqrt)676,
26.
The answer is supplementary.
Answer:
, graph is there for reference.
Step-by-step explanation:
Given,
is the number of math problem Lucy solved.
is the number of pages she read.
She can do each math problem in
minutes, therefore she can solve
number of questions into
minutes.
She can read each page in
minutes, therefore she can read
pages in 2.5y minutes.
As per given detail,
equation 1.
And,
It is given that number of math problems Lucy solved is 3 times the number of pages she read.
equation 2.
We need to find
and
intercept of each of the equation to graph them.
For
put y=0
We will get 
Thus the point is 
Let us find
by assuming 
we get 
Thus the point is 
Join these two points.
Similarly considering the other equation 
Here x-intercept would be at
We will get 
Thus the point is 
Let us assume on more point, say
, we get 
Thus the point is 
Join these two points.
We will get a point of intersection at 
Thus
and 