Answer:
D. vo = 125(2)^1/2
Step-by-step explanation:
Range of a projectile is the defined as the distance covered in the horizontal direction.
Range = U²sin2θ/g
U is the speed of the object
θ is the angle of launch
g is the acceleration due to gravity
If the target is 1000 ft away horizontally, range = 1000ft
θ = 45°
g = 32ft/s²
1000 = U²sin2(45°)/32
32000 =U²sin90°
32000 = U²
U = √32000
U = 125√2 m/s
Given:
The speed, s, is measured in miles per hour, and distance, y, is measured in yards.
The regression line is given by
...(i)
To find:
The slope and y-intercept of the regression line.
Solution:
The general form of linear regression line is
...(ii)
where x is variable. In the given equation the variable is denoted by s.
On comparing (i) and (ii), we get

It means slope is 52.45 and y-intercept is 4.17.
The slope, b = 52.45, indicates that the distance increases by 52.45 yards for every one mile per hour of speed.
The y-intercept, a = 4.17, is the distance estimated by this model if the speed is zero miles per hour.
Therefore, the correct option is A.
Answer:
(a+6)2=49 (use the distributive property and multiply 2 by everything left side
2a +12=49 (subtract 12 from both sides to isolate the a-term)
2a = 37 (divide both sides by 2 to get a alone)
a= 18.5 (this is your answer)
Step-by-step explanation:
I hope this helps :)