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zlopas [31]
3 years ago
9

Introduction: Match the type of bank to the phrase that best describes it.

Mathematics
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

Retail bank specializes in serving individuals for profit

Credit union is owned by its members

Savings and loan specializes in helping homeowners

Commercial bank specializes in serving large business

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A recipe used 2/3 of sugar for every 2 teaspoons of vanilla.how much sugar was used per teaspoon of vanilla.
mrs_skeptik [129]
Hi there,

The answer is 1/3 cup per teaspoon. Here’s how...


All you have to do is divided 2/3 by 2.

We have to put a 1 under the 2 to at least represent it as a fraction.

2/3 / 2/1

Next we flip 2/1 into 1/2.

2/3 / 1/2

Now we are going to multiply.

2x1=2

3x2=6

We get 2/6, simplifying that we get 1/3 cup per teaspoon.
8 0
3 years ago
Can you help me, I'm stuck
katrin [286]

Answer:

x=9

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
4 years ago
Determine the inverse for the function f(x)= 4x+20
LUCKY_DIMON [66]

Answer:

6.40

Step-by-step explanation:

5 0
3 years ago
You roll a fair six-sided die twice. The first roll shows a five and the second roll shows a six.
anyanavicka [17]

Answer:

<h2>1/36</h2>

Step-by-step explanation:

These are independent events, so we will just multiply the two probabilities together.

1/6 x 1/6 = 1/36

I'm always happy to help :)

6 0
4 years ago
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