It’s c since the line goes down 5 and the y intercept is 3 so it would be y=-5x+3
1.) f(x)=7(b)^x-2
x=0→f(0)=7(b)^0-2=7(1)-2=7-2→f(0)=5→(x,f(x))=(0,5) Ok
2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No
3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No
4.) f(x)=-5(b)^x+10
x=0→f(0)=-5(b)^0+10=-5(1)+10=-5+10→f(0)=5→(x,f(x))=(0,5) Ok
5.) f(x)=2(b)^x+5
x=0→f(0)=2(b)^0+5=2(1)+5=2+5→f(0)=7→(x,f(x))=(0,7) No
Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10
First find the number of ft around the garden and if it took Clare 30 min to walk the entire distance divide your previous answer by 30 so you can see how many ft per minute she was walking
Answer:
$793
Step-by-step explanation:
The amount of money in an account earning simple interest is given by the formula ...
A = P(1 +rt)
where P is the principal invested at rate r for t years.
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Using the values given in the problem statement, the account balance can be found to be ...
A = $650(1 +0.055×4) = $650×1.22 = $793
There will be $793 in the account after 4 years.
Use the formula speed=distance/time, or s=d/t.
Substitute 2,482 for d and 42.5 for t.
s=2,482/42.5
Simply divide for the answer:
Mr. Douglas' average speed for the trip was 58.4 miles per hour.
I hope this helps! ^_^
