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stira [4]
3 years ago
7

The graph of y = 5x2 is the graph of y = x2.

Mathematics
2 answers:
bezimeni [28]3 years ago
7 0

Answer:

Narrower than and opens in the same direction as......

Step-by-step explanation:

by inputting into a t1-83 calculator into the graph section, you can see the differences.

kicyunya [14]3 years ago
6 0

Answer:

narrower than and opens in the same direction as

Step-by-step explanation:

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I need to solve for 3x+7=-x-1
Andrew [12]

3x+7=-x-1

move -x to the other side

sign changes from -x to +x

3x+x+7=-x+x-1

3x+x+7=-1

4x+7=-1

move 7 to the other side

sign changes from +7 to -7

4x+7-7=-1-7

4x=-8

Divide by 4 for both sides

4x/4=-8/4

Answer: x=-2

3 0
3 years ago
What is the x intercept of y + 4 =− 4(x − 1)
vivado [14]

Answer:

0

Step-by-step explanation:

since the "b" in y=mx+b ends up being 0, that means that the y intercept is 0, which also means that the x intercept is 0.

7 0
2 years ago
a garden is in the shape of a rectangle 35 feet long and 29 feet wide. if fencing cost $7 a foot, what will it cost to plate fen
miskamm [114]
It would cost $896 to plate fencing around the garden
4 0
3 years ago
A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 450°F into a room that is a constant 70°F. After 5​
gladu [14]

Answer:

A) It will get to a temperature of 125°F at 9:19 PM

B) It will get to a temperature of 150°F at 9:16 PM

C) as time passes temperature approaches the initial temperature of 450°F

Step-by-step explanation:

We are given;

Initial temperature; T_i = 450°F

Room temperature; T_r = 70°F

From Newton's law of cooling, temperature after time (t) is given as;

T(t) = T_r + (T_i - T_r)e^(-kt)

Where k is cooling rate and t is time after the initial temperature.

Now, we are told that After 5​ minutes, the temperature is 300°F.

Thus;

300 = 70 + (450 - 70)e^(-5k)

300 - 70 = 380e^(-5k)

230/380 = e^(-5k)

e^(-5k) = 0.6053

-5k = In 0.6053

-5k = -0.502

k = 0.502/5

k = 0.1004 /min

A) Thus, at temperature of 125°F, we can find the time from;

125 = 70 + (450 - 70)e^(-0.1004t)

125 - 70 = 380e^(-0.1004t)

55/380 = e^(-0.1004t)

In (55/380) = -0.1004t

-0.1004t = -1.9328

t = 1.9328/0.1018

t ≈ 19 minutes

Thus, it will get to a temperature of 125°F at 9:19 PM

B) Thus, at temperature of 150°F, we can find the time from;

150 = 70 + (450 - 70)e^(-0.1004t)

150 - 70 = 380e^(-0.1004t)

80/380 = e^(-0.1004t)

In (80/380) = -0.1004t

-0.1004t = -1.5581

t = 1.5581/0.1004

t ≈ 16 minutes.

Thus, it will get to a temperature of 150°F at 9:16 PM

C) As time passes which means as it approaches to infinity, it means that e^(-kt) gets to 1.

Thus,we have;

T(t) = T_r + (T_i - T_r)

T_r will cancel out to give;

T(t) = T_i

Thus, as time passes temperature approaches the initial temperature of 450°F

6 0
3 years ago
RAM, HARI and SHYAM INVEST A SUM OF RS. 15000 ON A BUSINESS IN THE RATIO OF 4 : 5. FIND EACH OF THEIR INVESTMENT.
sashaice [31]

Answer:

hey iif ram hari n shyam invest then the ratio shall be like x:y:z but the qstn isnot . ram:hari:shyam =? it can't be 4:5 only it might be 4:5:?

3 0
3 years ago
Read 2 more answers
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