Answer:
"To the nearest year, it would be about 9 years"
Step-by-step explanation:
11c)
This is compound growth problem. It goes by the formula:
Where
F is the future amount
P is the present (initial) amount
r is the rate of growth, in decimal
t is the time in years
Given,
P = 20,000
r = 8% = 8/100 = 0.08
F = double of initial amount = 2 * 20,000 = 40,000
We need to find t:
To solve exponentials, we can take Natural Log (Ln) of both sides:
Using the rule shown below we can simplify and solve:
We can write:
To the nearest year, that would be about 9 years
Answer: The answer is 135 murders.
Step-by-step explanation: The report tells us that statistically 67.5% of murders are committed using a firearm. It follows therefore that in a sample of 200 randomly selected murders, one would expect that 67.5% of those would be by a firearm. 
* 200 = 135.
It would certainly be higher that the expected value based on previous data collected but it would not be unusual because one sample may have a higher than "normal" amount of murders by firearm. Statistics aren't going to be exact for every sample.
Answer:
Part A- The 1st box is 96 and the second box is 10.
PartB-
Part C-
Step-by-step explanation:
<h2><u><em>
Part A:</em></u></h2>
5x12=60
6x12=72
8x12=96
10x12=120
So the 1st box is 96 and the second box is 10.
<h2><u><em>
Part B:</em></u></h2>
5 $50
6 $60
8 $80
I know this because Harry receives $10 per hour so you have to multiply the number of hours by $10.
<h2>
<em><u>Part C:</u></em></h2>
If Harry babysits for 5 hours, he would receive $60 but if he does yard work for 5 hours, he would receive $50. Harry would receive $10 more by babysitting than by doing yard work.
Hoped this helped.
Answer:
(a) 283 days
(b) 248 days
Step-by-step explanation:
The complete question is:
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?
Solution:
The random variable <em>X</em> can be defined as the pregnancy length in days.
Then, from the provided information 
.
(a)
The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:
P (X > x) = 0.11
⇒ P (Z > z) = 0.11
⇒ <em>z</em> = 1.23
Compute the value of <em>x</em> as follows:
Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.
(b)
The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:
P (X < x) = 0.05
⇒ P (Z < z) = 0.05
⇒ <em>z</em> = -1.645
Compute the value of <em>x</em> as follows:
Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.
Answer:
ty
Step-by-step explanation:
pls mark brainliest
