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Semmy [17]
4 years ago
15

In a fruit cocktail, for every 28 ml of orange juice you need 14 ml of apple juice and 56 ml of coconut milk. What is the ratio

of apple juice to coconut milk to orange juice expressed in its simplest form?
Mathematics
1 answer:
ludmilkaskok [199]4 years ago
5 0

Answer:

1 : 4 : 2.

Step-by-step explanation:

Ratio is 14:56:528

Divide each number by 14 to get the answer:-

1 : 4 : 2.

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20 increased by ??? is 35 <br> options are <br> 125%<br> 200%<br> 75%<br> 150%
morpeh [17]
75%

explanation: it can’t be above 100% because that would be over 40.
8 0
3 years ago
Find the exact value by using a half-angle identity.<br><br> tan seven pi divided by eight
murzikaleks [220]

9514 1404 393

Answer:

  1 -√2

Step-by-step explanation:

  \tan(x/2)=\dfrac{1-\cos(x)}{\sin(x)}\\\\\tan\left(\dfrac{1}{2}\cdot\dfrac{7\pi}{4}\right)=\dfrac{1-\cos\dfrac{7\pi}{4}}{\sin\dfrac{7\pi}{4}}=\dfrac{1-\dfrac{1}{\sqrt{2}}}{-\dfrac{1}{\sqrt{2}}}=\boxed{1-\sqrt{2}}

tan(7π/8) = 1 -√2

7 0
3 years ago
What is 9 to the of 3
MrRa [10]

Answer:

729

Step-by-step explanation:

8 0
2 years ago
PLEASE HELP ASAP I DON'T UNDERSTAND
Ira Lisetskai [31]
The slope of a linear equation will tell you the price of each ticket. The y-intercept tells you the convenience fee.
We can find the slope by choosing two points and finding the slope.
m = (y2 - y1)/(x2 - x1)
m = (887.40 - 231.15)/(20 - 5)
m = 656.25/15
m = 43.75
Each ticket will cost $43.75
4 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
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