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3 years ago

Which of the following is a proportion? Please help!! D:

Mathematics

1 answer:

natima [27]3 years ago

4 0

Answer:

the second one

Step-by-step explanation:

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Can anyone solve this asap? i’m completing a final.

Allisa [31]

Answer:

Step-by-step explanation:

The right option es a)

because the general form is:

ax^2+bx+c

so you can easyly identify b=-5

7 0

3 years ago

Find the product <br> (4p + 6)( 7p -5)

sleet_krkn [62]

Answer:

28p^2+22p-30

Step-by-step explanation:

I'm a genius

3 0

2 years ago

Isabella's rain gauge showed 3 centimeters/cra) last Tuesday. This Tuesday,

Llana [10]

<h3><u>Question:</u></h3>

Isabella’s rain gauge showed 3 4/5 centimeters (cm) last Tuesday. This Tuesday, the rain gauge showed 5 7/10 centimeters. How many more centimeters of rain fell during the week?

A 9 1/2cm B 8 1/2cm c 2 4/5cm D 1 9/10 cm

<h3><u>Answer:</u></h3>

Option D

$1\frac{9}{10}$ more centimeters of rain fell during this week than last week

<h3><u>Solution:</u></h3>

From given,

$Last\ tuesday = 3\frac{4}{5}\ cm\\\\Convert\ to\ improper\ fraction\\\\Last\ tuesday = \frac{5 \times 3 + 4}{5} = \frac{19}{5}\ cm$

Also given that,

$This\ tuesday = 5\frac{7}{10}\ cm = \frac{10 \times 5 + 7}{10} = \frac{57}{10}\ cm$

<em><u>How many more centimeters of rain fell during the week?</u></em>

$This\ tuesday - last\ tuesday = \frac{57}{10} - \frac{19}{5}\\\\This\ tuesday - last\ tuesday = \frac{57}{10} - \frac{19 \times 2}{5 \times 2}\\\\This\ tuesday - last\ tuesday = \frac{57-38}{10}\\\\This\ tuesday - last\ tuesday = \frac{19}{10}\\\\Converting\ to\ mixed\ fraction\\\\\rightarrow \frac{19}{10} = 1\frac{9}{10}$

Thus $1\frac{9}{10}$ more centimeters of rain fell during this week than last week

8 0

2 years ago

ANSWER FAST

brilliants [131]

Answer:

y = 1

Step-by-step explanation:

x + y = 16

x - y = 14 add the equations

--------------

2x = 30

x = 15

x + y = 16

15 + y = 16

y = 1

the numbers are 15 and 1

7 0

3 years ago

4x - 7y = 3 <br> x - 7y = 15

charle [14.2K]

$\left \{ {{4x-7y=3} \atop {x-7y=15}} \right. \\\\
 \left \{ {{4x-7y=3} \atop {x=15+7y}} \right. \\\\ substitution\ method\\\\
4*(15+7y)-7y=3\\\\
60+28y-7y=3\\\\
60+21y=3\ \ \ \ | subtract\ \\\\
21y=-57\\\\
y=-\frac{57}{21}=-\frac{19}{7}\\\\
x=15+7*(-\frac{19}{7})=15-19=-4\\\\\ Solution :\ \left \{ {{y=-\frac{19}{7}} \atop {x=-4}} \right.$

5 0

3 years ago