Fractions they are easy REALLY!!
A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer:
47.8°
Step-by-step explanation:
Let's first outline the important parameters
--- <V = 90°
Vt = 64
UV = 43
The angles in a triangle sums up to 180,but we don't have up to 2 angles given so as to find the third one. What we have to is to find the second angle,in this case T,using the sine rule.
Sin v/v = sin t/t
(Sin 90)/64 = sin t/43
Cross multiply and we have
43 sin 90 = 64 sin t
Sin t = 43 sin 90 ÷ 64
Sin t = 0.6719
Sine inverse of t = 42.2°(the second angle)
Angle U = 180 -( 90 + 42.2)
180 - 132.2
= 47.8°
24 times 2 pencils each student is 48 then you divide by 8 to get the number of packages needed which is 8.
