In May you used 900 kilowatt-hours of energy for electricity.
1 answer:
Answer:
a) "The total electrical energy use was 3,240,000,000 joules."
b) "The average power use is 1210 watts."
c)
<u>Part 1:</u> "To generate the electricity you used, 810 L is needed."
<u>Part 2:</u> "To generate the electricity you used, 214.00 gal is needed."
Step-by-step explanation:
a)
1 kilowatt-hours = joules
Converting 900 kilowatt-hours to joules, we have:
joules, or
Total Electrical Energy use = 3,240,000,000 joules
"The total electrical energy use was 3,240,000,000 joules."
b)
The month of May has 31 days and 1 day is 24 hours. So May has:
31*24=744 hours
Now, we divide 900 kW-hr by the number of hours in the month (744 hrs) to get average power use:
kW. Since 1000 Watts = 1 kW, we multiply this by 1000 to get the answer in Watts:
1.21 * 1000 = 1210 Watts
"The average power use is 1210 watts."
c)
<u>Part 1:</u>
The conversion efficiency of most generating stations is 33%. So we need to multiply the total electrical energy use (in joules) by a factor of 3 to get the amount of joules required. So:
(3.24 * 10^9)*3 = 9.72 * 10^9 joules
We divide this by 12 million joules to get the number of liters:
So, 810 liters is needed
"To generate the electricity you used, 810 L is needed."
<u>Part 2:</u>
We know that 0.2642 gallons is equal to 1 liters. To get the number of gallons needed, we multiply 810 by 0.2642. So:
810 * 0.2642 = 214.00 gallons
"To generate the electricity you used, 214.00 gal is needed."
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