Question

In May you used 900 ​kilowatt-hours of energy for electricity.

Answer 1

Answer:

a) "The total electrical energy use was 3,240,000,000 joules."

b) "The average power use is 1210 watts."

c)

Part 1: "To generate the electricity you​ used, 810 L is needed."

Part 2: "To generate the electricity you​ used, 214.00 gal is needed."

Step-by-step explanation:

a)

1 kilowatt-hours = $3.6x10^6$ joules

Converting 900 kilowatt-hours to joules, we have:

$900*(3.6*10^6)=3.24*10^9$ joules, or

Total Electrical Energy use = 3,240,000,000 joules

"The total electrical energy use was 3,240,000,000 joules."

b)

The month of May has 31 days and 1 day  is 24 hours. So May has:

31*24=744 hours

Now, we divide 900 kW-hr by the number of hours in the month (744 hrs) to get average power use:

$\frac{900}{744}=1.21$ kW. Since 1000 Watts = 1 kW, we multiply this by 1000 to get the answer in Watts:

1.21 * 1000 = 1210 Watts

"The average power use is 1210 watts."

c)

Part 1:

The conversion efficiency of most generating stations is 33%. So we need to multiply the total electrical energy use (in joules) by a factor of 3 to get the amount of joules required. So:

(3.24 * 10^9)*3 = 9.72 * 10^9 joules

We divide this by 12 million joules to get the number of liters:

$\frac{9.72*10^9}{12*10^6}=810$

So, 810 liters is needed

"To generate the electricity you​ used, 810 L is needed."

Part 2:

We know that 0.2642 gallons is equal to 1 liters. To get the number of gallons needed, we multiply 810 by 0.2642. So:

810 * 0.2642 = 214.00 gallons

"To generate the electricity you​ used, 214.00 gal is needed."