Choose a variable, write an equation for each problem and solve the problem
1 answer:
You might be interested in
First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins
<em><u>Solution:</u></em>
Given that,
Total number of coins = 200
Number of bags = 4
<em><u>I put the coins into each bag so that each bag has 2 more coins than the one before</u></em>
Therefore,
Each bag has 2 more coins than the one before. Based on this we can say,
Let "x" be the number of coins put in first bag
Then, x + 2 is the number of coins put in second bag
Then, x + 4 is the number of coins put in third bag
Then, x + 6 is the number of coins put in fourth bag
We know that,
Total number of coins = 200
Thus,
Coins put in first bag = x = 47
Coins put in second bag = x + 2 = 47 + 2 = 49
Coins put in third bag = x + 4 = 47 + 4 = 51
Coins put in fourth bag = x + 6 = 47 + 6 = 53
Thus number of coins in each bag are found
Answer:
- Let p be the population at t be the number of years since 2011. Then,
- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then,
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get
Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get
Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students