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quester [9]
3 years ago
8

The ratio of the number of coins to the number of notes Mrs James has in her purse is 2 : 5.

Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Answer:

85 notes

Step-by-step explanation:

2 coins : 5 notes

1 coin   :    2.5 notes

34 coins : __ notes

^

I

I

(multiply by 2.5 to get amount of notes)

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5 0
2 years ago
Question 9 (1 point)
Romashka [77]

Answer:

Step-by-step explanation:

League A                   League B

151.12                            163.25

148                                157

26.83                             24.93

29                                  136

136                                145

167                                178

207                               256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(82.5-1.5\times 76.56,159.06+1.5\times 76.56)

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(140.5-1.5\times 30.125,170.625+1.5\times 30.125)

(95.3125,215.8125)

24.93 and 256 are outliers  

Maximum = 256

5 0
3 years ago
Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up. What are
tankabanditka [31]

The coordinates of point B' are (-3, 6).

<h2>Given that</h2>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

<h3>We have to determine</h3>

What are the coordinates of B' after the translation?

<h3>According to the question</h3>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.

After the given transformation the coordinates of point B' would be:

\rm B(0, \ 5) = B (0-3, \ 5+1) = B(-3, \ 6)

Therefore, the coordinates of point B' are (-3, 6).

To know more about Transformation click the link given below.

brainly.com/question/26297555

6 0
3 years ago
Help me please it’s math so... yea.... a b c d e f g h I j k l m n o p q r s t u v w x y z
Ugo [173]
Answer= 16

Work=
1. Multiply each side by 1/5 (aka divide them by 5). This leaves 3, 4 and 9.

2. Add all the sides. 3 + 4 + 9 = 16. That is the perimeter
3 0
3 years ago
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