Since it’s a square we know that GJ has to be the same as GH. To find a diagonal you would do a^2 + b^2 = c^2. Which gives us about 9.19. So GJ=6.5 and JH=9.2
Answer:
10.3 units
Step-by-step explanation:
Recall: SOHCAHTOA
Reference angle = 69°
Side length Opposite to reference angle = x
Hypotenuse length = 11
Thus, apply the trigonometric ratio, SOH:
Sin 69 = Opp/Hyp
Substitute
Sin 69 = x/11
11 × Sin 69 = x
10.2693847 = x
x = 10.3 units (nearest tenth)
The answer for this question is 65.099 or when round off to two decimal places, it will be 65.10
<h3>
Answer: 38.1</h3>
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Explanation:
Segment AB is tangent to circle C. That tells us angle ABC is a 90 degree angle (the tangent is always perpendicular to the radius at the point of tangency). In other words, segments AB and BC are perpendicular. So triangle ABC is a right triangle.
The hypotenuse is AC = 22+22 = 44 units. One of the legs is BC = 22 units, due to the fact that radii of the same circle are the same length.
We then use the pythagorean theorem to find the missing leg length.
(AB)^2 + (BC)^2 = (AC)^2
(AB)^2 + (22)^2 = (44)^2
(AB)^2 + 484 = 1936
(AB)^2 = 1936 - 484
(AB)^2 = 1452
AB = sqrt(1452)
AB = 38.105118 which is approximate
AB = 38.1 after rounding to the nearest tenth
