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tresset_1 [31]
3 years ago
14

A) {y=2x

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0

We can see that

both lines intersects at origin

so, the solution is x=0 and y=0

now, we will check each options

option-A:

y=2x

y=-4x

now, we can set them equal

and then we can solve for x

-4x=2x

6x=0

x=0

now, we can find y

y=2*0

y=0

so, solution is x=0 and y=0

so, this correct...........Answer


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15h - m = 13h + q pleas helppp
tensa zangetsu [6.8K]
I don’t know what I’m solving for so I solved for h and with that it should be h=q/2+m/2

Explanation:

15h-m=13h+q
-13h -13h
———————-
2h-m=q
+m +m
———————-
2h=q+m
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———————-
H=q/2+m/2

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Solve for x. This figure is a parallelogram
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Answer:

x=9

Step-by-step explanation:

Since you don't have that much information, you have to assume line HE is congruent to line GF, so now you have an equation that looks like this:  23=x+14.  Now you subtract 14 from both sides giving you 9=x, and since you cannot simplify even further, that is your answer

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3 years ago
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Fourteen square units
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2 years ago
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ZE and ZF are vertical angles with mZE = 8x + 8 and mZF = 2x +38.<br> What is the value of x?
Dovator [93]

Answer:

Since ZE and ZF are vertical angles, they are congruent.

8x+8 = 2x+38

8 = 2x-8x+38

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x = -30/-6

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7 0
3 years ago
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A metalworker has a metal alloy that is 15​% copper and another alloy that is 75​% copper. How many kilograms of each alloy shou
lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

<em><u>Solution:</u></em>

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

<em><u>Solve the equation for "x"</u></em>

15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0
2 years ago
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