30000 is the estimate if your estimating by the ten thousand
If I’m doing it correctly it’s 2/3 but I haven’t done it in a while
Answer:
6
Step-by-step explanation:
The given expression is ![36^{\frac{1}{2}}](https://tex.z-dn.net/?f=36%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
We rewrite using property of exponents to get;
![(6^2)^{\frac{1}{2}}=(6)^{2\times \frac{1}{2}}](https://tex.z-dn.net/?f=%286%5E2%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%286%29%5E%7B2%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%7D)
This gives
![(6)^{2\times \frac{1}{2}}=6^1=6](https://tex.z-dn.net/?f=%286%29%5E%7B2%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%7D%3D6%5E1%3D6)
Or simplify;
![36^{\frac{1}{2} }=\sqrt{36} =6](https://tex.z-dn.net/?f=36%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%3D%5Csqrt%7B36%7D%20%3D6)
Hello,
Answer A: y=x²-25
x-interscept must be 5 and 5 : a vertex in (5,0))
Answer:
First car: 30 gallons
Second car: 35 gallons
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations:
Total gas consumption was 65:
x+y=65
Where:
x = gallons consumed by the first car
y = gallons consumed by the second car
The first car has a fuel efficiency of 20 miles per gallon of gas and the second has a fuel efficiency of 30 miles per gallon of gas, the two cars went a combined total of 1650 miles:
x 20+y 30 = 1650
The system is:
x+y=65 (1)
x 20+y 30 = 1650 (2)
Isolating y on (1)
y = 65-x
Replacing y= 65-x on (2):
x 20+(65-x)30 = 1650
20x +1,950-30x= 1650
20x-30x= 1650-1950
-10x= -300
x= -300/-10
x = 30 gallons
Back to (1)
y =65-x
y =65-30
y= 35 gallons
Feel free to ask for more if needed or if you did not understand something.