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Marina86 [1]
3 years ago
7

What is 67 divided by 6 and what is the remainder

Mathematics
2 answers:
ahrayia [7]3 years ago
7 0
6 x 11= 66
67 - 66 = 1

67/6 = 11 
remainder= 1
irakobra [83]3 years ago
6 0
The actual answer is 11.1666666667 but my guess is 11.7 or 11.9 
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Solve the system of equations.
guajiro [1.7K]

Answer:

Option 2: (1, 0) and (0, -5)

Step-by-step explanation:

Let's solve this system of equations using the elimination method.

Start by labelling the two equations.

5x -y= 5 -----(1)

5x² -y= 5 -----(2)

(2) -(1):

5x² -y -(5x -y)= 5 -5

Expand:

5x² -y -5x +y= 0

5x² -5x= 0

Factorise:

5x(x -1)= 0

5x= 0 or x -1= 0

x= 0 or x= 1

Now that we have found the x values, we can substitute them into either equations to solve for y.

Substitute into (1):

5(0) -y= 5 or 5(1) -y= 5

0 -y= 5 or -y= 5 -5

y= -5 or -y= 0

y= 0

Thus, the solutions are (0, -5) and (1, 0).

3 0
2 years ago
If the measure of angle 4 is (11 x) degrees and angle 3 is (4 x) degrees, what is the measure of angle 3 in degrees?
GarryVolchara [31]

Answer:

B

Step-by-step explanation:

Angle 4 × Angle 3 = 90

Complementary angles

11x + 4x = 90

15x = 90

x = 6

Angle 3 = 4x = 4(6) = 24°

5 0
3 years ago
Read 2 more answers
1- (-6k + 6) < 3k +1 + 5k
rjkz [21]

Answer:

k>5/14

Step-by-step explanation:

4 0
3 years ago
The blue dot is at what value on the number line?<br> ?<br> -8<br> -10
lesya692 [45]

Answer:

I think the answer is negative five (-5)

8 0
3 years ago
A bag contains 3 pink gumballs, 4 red gumballs, and 2 green gumballs. Find the probability that a red gumball is drawn if there
fgiga [73]

Answer:

0.99

Step-by-step explanation:

Given,

Pink gumballs = 3,

Red gumballs = 4,

Green gumballs = 2,

So, total gumballs = 3 + 4 + 2 = 9,

Thus, total ways of selecting 5 gumball = ^9C_5

=\frac{9!}{5!4!}

=\frac{9\times 8\times 7\times 6}{24}

=9\times 2\times 7

=126

Also, the total ways of selecting no red gumballs = ^4C_0\times ^5C_5

= 1 × 1

= 1

So, the probability of no red gumballs in 5 drawn

=\frac{1}{126}

Hence, the probability that a red gumball is drawn if there are 5 drawings

= 1 - probability of no red gumballs

=1-\frac{1}{126}

=\frac{125}{126}

≈ 0.99

8 0
3 years ago
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