The volume of the cube is 9
A solution with a pH of 11 has a [H+] of 
Option B is correct option.
Step-by-step explanation:
A solution with a pH of 11 has a [H+] of= ?
pH=?
Concentration of H+ [H+]= ?
Formula used: ![pH=-log[H+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%2B%5D)
Putting values and finding [H+]
![pH=-log[H+]\\\,[H+]\,=10^{-pH}\\\,[H+]\,=10^{-11}\\\,[H+]\,=1.0\times 10^{-11}](https://tex.z-dn.net/?f=pH%3D-log%5BH%2B%5D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D10%5E%7B-pH%7D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D10%5E%7B-11%7D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D1.0%5Ctimes%2010%5E%7B-11%7D)
So, A solution with a pH of 11 has a [H+] of
Option B is correct option.
25 percent is the same as the decimal 0.25.
Multiply 100 by 0.25 to see what 25% of 100 is.
100x0.25=25
Then, to find the price raised by 25%, add 25 to 100.
100+25=125
The final answer is $125.
Hope this helps!
Answer:
You will need 20 sides to complete the loop.
Step-by-step explanation:
The question isn't quite clear given how small the corner is, but I assume that we are looking to complete the circle if the pentagon and square are repeated in a loop
We can also see - assuming that those are proper equal-sided polygons, that PQ is the same length as PV
With that in mind, We can solve this by noting that the angle of a corner in a square is 90 degrees, and in a pentagon it's 108 degrees.
108 - 90 is equal to 18. This means that PQ is at eighteen degrees to YP. Also, QM, (which will be equivalent to the next VP is eighteen degrees to PQ.
This means that each polygon is rotated 18 degrees relative to it's neighbour.
With all that we can say that the total polygons we need to form a circle is 360/18 = 20, So you will need 20 polygons, or ten squares and ten pentagons to complete the loop.
Y=-4x+3-x because if it's -y=4-3+x y is not alone so you need to make y positive and switch the rest of the operations so it can be y=-4+3-x
