Question

Simplify the rational expression.  State any restrictions on the variable.

Answer 1

Answer:

The last choice.

Step-by-step explanation:

$\dfrac{k^2-k-2}{k^2-4k-5}=\dfrac{(k+1)(k-2)}{(k+1)(k-5)}=\dfrac{k-2}{k-5}$

The value of k must be restricted from being one that makes the original denominator zero. Hence k ≠ -1 or 5.