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svetlana [45]
3 years ago
9

A group of students travel 14 miles in 3 days. If they travel the same amount of miles each day, about how many miles does the g

roup travels each day?
Mathematics
1 answer:
borishaifa [10]3 years ago
5 0

Answer:

About 4.5

Step-by-step explanation:

14 / 3 ≈ 4.5

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The price of a car has been reduced from $15,000 to $9,000. What is the percentage decrease of the price of the car?
Fynjy0 [20]

Answer:

40<em>% is the decrease.</em>

<em />

Step-by-step explanation:

<em>To figure out the percentage decrease, you would first subtract the two numbers. </em>

<em />

<em />15000 - 9000 = 6000<em />

<em />

<em>Next, you would divide that number by the total.</em>

<em />

<em />6000 / 15000 = .4<em />

<em />

<em />15000 * .4 = 6000<em />

<em />

<em />15000 - 6000 = 9000<em />

<em />

<em />40<em>% </em><em>would be the decrease percentage. </em>

3 0
3 years ago
Need this one giving lots of points b/c im lazy and i have a headache
charle [14.2K]
B
1/4 = 8/3 * x
X = 8/12
X= 2/3
8 0
3 years ago
Find the indicated probability. The weekly salaries of teachers in one state are normally distributed with a mean of $490 and a
Alecsey [184]

Given Information:

Mean weekly salary = μ = $490

Standard deviation of weekly salary = σ = $45

Required Information:

P(X > $525) = ?

Answer:

P(X > $525) = 21.77%

Step-by-step explanation:

We want to find out the probability that a randomly selected teacher earns more than $525 a week.

P(X > 525) = 1 - P(X < 525)\\\\P(X > 525) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\P(X > 525) = 1 - P(Z < \frac{525 - 490}{45} )\\\\P(X > 525) = 1 - P(Z < \frac{35}{45} )\\\\P(X > 525) = 1 - P(Z < 0.78)\\\\

The z-score corresponding to 0.78 from the z-table is 0.7823

P(X > 525) = 1 - 0.7823\\\\P(X > 525) = 0.2177\\\\P(X > 525) = 21.77 \%

Therefore, there is 21.77% probability that a randomly selected teacher earns more than $525 a week.

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 0.7, 2.2, 1.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.78 then go for 0.08 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

3 0
3 years ago
This is a double question. Part 1: 5(2x - 4) = 30. Solve for x Part 2: 5x + 3 - x + 2 = 41. Solve for x. I will mark Brainliest
Ainat [17]

Answer:

see below

Step-by-step explanation:

Part 1: 5(2x - 4) = 30.

Distribute

10x -20 = 30

Add 20 to each side

10x-20+20 =30+20

10x = 50

Divide by 10

10x/10 = 50/10

x =5

Part 2: 5x + 3 - x + 2 = 41

Combine like terms

4x +5 = 41

Subtract 5 from each side

4x+5-5 = 41-5

4x = 36

Divide by 4

4x/4 = 36/4

x = 9

3 0
3 years ago
Read 2 more answers
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
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