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matrenka [14]
3 years ago
14

What's the nth term of the sequence 6,10,14,18,22

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0

The Nth term of the sequence is

               T(n)  =  2 + 4n  or    <em>2 (2n + 1)</em> .


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Solve for w.<br> 8(w+2) = 40
AleksAgata [21]

Answer:

  w = 3

Step-by-step explanation:

 8 • (w + 2) -  40  = 0

Pulling out like terms :

3.1     Pull out like factors :

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Equation at the end of step  3  :

 8 • (w - 3)  = 0

Step  4  :

Equations which are never true :

4.1      Solve :    8   =  0

This equation has no solution.

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Solving a Single Variable Equation :

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One solution was found :

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7 0
3 years ago
Find the shortest distance, d, from the point (5, 0, −6) to the plane x + y + z = 6.
DENIUS [597]

Answer:

\frac{7}{\sqrt{3}}

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |                   --------------------(i)

From the question,

the point is (5, 0, -6)

the plane is x + y + z = 6

Therefore,

a = 5

b = 0

c = -6

m = 1

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t = 1

r = 6

Substitute these values into equation (i) as follows;

d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |

d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |

d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

Therefore, the shortest distance from the point to the plane is  d = \frac{7}{\sqrt{3}}

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3 years ago
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The correct answer for USATesprep is


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Answer:

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