Answer:
rjogir
grggreijgojrejow
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Step-by-step explanation:
I think it is 9 - x because 81-x^2/9-x = 9-x
Answer:
Step-by-step explanation:
<em>Hey there!</em>
3x * x = 3x^2
3x * 2x = 6x^3
So 3x is a factor of 3x^2 - 6x^3.
<em>Hope this helps :)</em>
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
