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zloy xaker [14]
3 years ago
9

The value of x that satisfies the equation 4/3=x+10/15

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

For this case we must find the value of "x" that meets the following equation:

\frac {4} {3} = x + \frac {10} {15}

We subtract \frac {10} {15} on both sides of the equation:

\frac {4} {3} - \frac {10} {15} = x\\\frac {15 * 4-3 * 10} {3 * 15} = x\\\frac {60-30} {45} = x\\- \frac {30} {45} = x

We simplify:

x =\frac {6} {9}=\frac{2}{3}

Finally, x =\frac {2} {3}

Answer:

x =\frac {2} {3}

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g100num [7]

Answer:

A

Step-by-step explanation:

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3 years ago
Use the substitution method to solve the following system of equations: 3x + 5y = 3 x + 2y = 0 (1 point) (1, 1) (6, −3) (6, 1) (
PtichkaEL [24]

Step-by-step explanation:

Given.

3x+5y=3

x+2y=0

Take the second equation and subtract 2y to both sides.

(x+2y)-2y=0-2y

x=-2y

Substitute x into the first equation and simplify.

3x+5y=3

3(-2y)+5y=3

-6y+5y=3

-y=3

Invert.

y=-3

Substitute Y into your second equation.

x+2y=0

x+2(-3)=0

x-6=0

Add -6 to both sides.

(x-6)+6=0+6

x=6

Answer:

(6, -3)

6 0
3 years ago
Make a conjecture about the next item in the sequence<br> 1, 1, 2, 3, 5, 8
Marizza181 [45]
It would be 13 because you are adding 5 and 8
6 0
3 years ago
Read 2 more answers
PLEASE HELP<br> How to do this
Ne4ueva [31]
I believe 20 is your answer. Tell me if I’m wrong.
4 0
3 years ago
Let S denote the plane region bounded by the following curves:
oee [108]

The volume of the solid of revolution is approximately 37439.394 cubic units.

<h3>How to find the solid of revolution enclosed by two functions</h3>

Let be f(x) = e^{\frac{x}{6} } and g(x) = e^{\frac{35}{6} }, whose points of intersection are (x_{1},y_{1}) =(0,1), (x_{2}, y_{2}) = (35, e^{35/6}), respectively. The formula for the solid of revolution generated about the y-axis is:

V = \pi \int\limits^{e^{35/6}}_{1} {f(y)} \, dy (1)

Now we proceed to solve the integral: f(y) = 6\cdot \ln y

V = \pi \int\limits^{e^{35/6}}_{1} {6\cdot \ln y} \, dy (2)

V = 6\pi \int\limits^{e^{35/6}}_{1} {\ln y} \, dy

V = 6\pi \left[(y-1)\cdot \ln y\right]\right|_{1}^{e^{35/6}}

V = 6\pi \cdot \left[(e^{35/6}-1)\cdot \left(\frac{35}{6} \right)-(1-1)\cdot 0\right]

V = 35\pi\cdot (e^{35/6}-1)

V \approx 37439.392

The volume of the solid of revolution is approximately 37439.394 cubic units. \blacksquare

To learn more on solids of revolution, we kindly invite to check this verified question: brainly.com/question/338504

8 0
2 years ago
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