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zloy xaker [14]
3 years ago
9

The value of x that satisfies the equation 4/3=x+10/15

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

For this case we must find the value of "x" that meets the following equation:

\frac {4} {3} = x + \frac {10} {15}

We subtract \frac {10} {15} on both sides of the equation:

\frac {4} {3} - \frac {10} {15} = x\\\frac {15 * 4-3 * 10} {3 * 15} = x\\\frac {60-30} {45} = x\\- \frac {30} {45} = x

We simplify:

x =\frac {6} {9}=\frac{2}{3}

Finally, x =\frac {2} {3}

Answer:

x =\frac {2} {3}

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Exhibit B: A restaurant has tracked the number of meals served at lunch over the last four weeks. The data shows little in terms
Mekhanik [1.2K]

Answer:

Option E is correct.

The expected number of meals expected to be served on Wednesday in week 5 = 74.2

Step-by-step Explanation:

We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.

Week

Day 1 2 3 4 | Total

Sunday 40 35 39 43 | 157

Monday 54 55 51 59 | 219

Tuesday 61 60 65 64 | 250

Wednesday 72 77 78 69 | 296

Thursday 89 80 81 79 | 329

Friday 91 90 99 95 | 375

Saturday 80 82 81 83 | 326

Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952

Total number of meals served at lunch on Wednesdays over the 4 weeks = 296

Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443

Total number of meals expected to be served in week 5 = 490

Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3

Checking the options,

74.3 ≈ 74.2

Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2

Hope this Helps!!!

8 0
2 years ago
7j + 5 - 8k when j = 0.5 and k = 0.25
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
C
Rama09 [41]

Answer:

  • m∠AOB=139°

Step-by-step explanation:

m∠AOB+m∠BOC=180°

m∠AOB=8x+51°

m∠BOC=6x-25°

~

\tt 8x+51+6x-25=180

\tt 14x+26=180

\tt 14x=180-26

\tt \cfrac{14x}{14} =\cfrac{154}{14}

\tt x=11

m∠AOB:-

\tt 8(11)+51

\tt =88+51

\tt =139^{o}

Therefore, m∠AOB=139°

7 0
2 years ago
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