Answer:
Step-by-step explanation:
(x+3)² -5 =0 , use the formula (a+b) ² = a²+b²+2ab
x²+9 +6x -5 =0 , combine like terms
x²+6x +4 =0, use the quadratic formula x = (-b±√b²-4ac)/2a
x= (-6 ±√6²-4*1*4)/2*1
x= (-6 ± √36-16) /2
x= (-6±√20)/2
x=(-6 +2√5)/2 and x=( -6-2√5) /2, factor 2 in the numerator and simplify
x= -3 +√5 and x= -3 -√5
The answer
the complement of the question is
What is the value of y?
2
5
7
<span>8
</span>
According to the image, HKJ and FGH are similar, we can apply the theorem of thales
since GK and GF are parallels, so
HK / HF = HJ / HG = KJ / GF and as we see on the figure, HK = HF /2, this implies 2HK =HF
HK / 2HK = KJ / GF it is equivalent to 1/2 = 2y+5 / 5y +3
likewise, equivalent to 5y +3 = 4y +10, 5y-4y = 10-3, and y = 7
so the answer is 7
On the right side we have st which is the same as s*t or s times t
We want to undo the multiplication that is happening to s, so we have to divide both sides by t
d = s*t
d/t = s*t/t ..... divide both sides by t
d/t = s
s = d/t
Answer: Choice A)
<u>Differentiate using the Quotient Rule</u> –
![\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\](https://tex.z-dn.net/?f=%5Cpink%7B%5Ctwoheadrightarrow%20%5Csf%20%5Cdfrac%7Bd%7D%7Bdx%7D%20%5Cbigg%5B%5Cdfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%20%5Cbigg%5D%3D%20%5Cdfrac%7B%20g%28x%29%5C%3A%5Cdfrac%7Bd%7D%7Bdx%7D%5Cbigg%5Bf%28x%29%5Cbigg%5D%20-f%28x%29%5Cdfrac%7Bd%7D%7Bdx%7D%5C%3A%5Cbigg%5Bg%28x%29%5Cbigg%5D%7D%7Bg%28x%29%5E2%7D%7D%5C%5C)
According to the given question, we have –
- f(x) = x^3+5x+2
- g(x) = x^2-1
Let's solve it!
![\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\](https://tex.z-dn.net/?f=%5Cgreen%7B%5Ctwoheadrightarrow%20%5Cbf%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Cbigg%5B%20%5Cdfrac%7Bx%5E3%2B5x%2B2%20%7D%7Bx%5E2-1%7D%5Cbigg%5D%7D%20%5C%5C)
