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Ratling [72]
3 years ago
8

I need help on this. Can someone explain it?

Mathematics
2 answers:
kozerog [31]3 years ago
5 0

Answer:

noooooooooooooooooooooo

Kruka [31]3 years ago
5 0
I’ve attached my work....
Hope it helps!
Have a nice day or night :O
Any concerns just comment and I can respond

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HELP ASAP!!! For the cube, x represents a positive whole number. Find the value of x such that the volume of the cube and 6 time
jonny [76]
Volume = wlh=x^3
surface area= 6x^2
x^3=6x^2
Divide by ^2 on both sides
x=6

7 0
3 years ago
Question 3 of 10 What is the slope of the line shown below? C O A. 5 5 (3,7) B. 2 O D.-2​
scoundrel [369]

Slope = Y2-Y1/X2-X1 = 7-(-3)/3-(-2)= 10/5 = 2

8 0
3 years ago
Read 2 more answers
What’s 18x3+12-1x34+13-2x56?
Alina [70]

18 x 3 + 12 - 1 x 34 + 13 - 2 x 56 = 67

<=Work=>

18 x 3 = 54

1 x 34 = 34

2 x 56 = 112

(54) + 12 - (34) + 13 - (112)

66 - 34 + 13 - 112

32 + 13 - 112

45 - 112

= 67

8 0
3 years ago
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Divide (x^3+2x^2-x-2) by (x-1)
Ymorist [56]
\frac{x^3+2x^2-x-2}{(x-1)} =x^2+3x+2 \\  \\ x^3+2x^2-x-2= \\= x^2(x+2)-(x+2) \\ =(x+2)(x^2-1)=(x+2)(x-1)(x+1) \\  \\  \frac{x^3+2x^2-x-2}{(x-1)}  = \frac{(x+2)(x-1)(x+1)}{x-1} =(x+2)(x+1)=x^2+3x+2
7 0
3 years ago
The function y = x 2 - 10x + 31 has a ____
katrin [286]

Answer:

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

Step-by-step explanation:

In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.

Given function is:

f(x) = x^2-10x+31

Taking first derivative

f'(x) = 2x-10

Now the first derivative has to be put equal to zero to find the critical value

2x-10 = 0\\2x = 10\\x = \frac{10}{2} = 5

The function has only one critical value which is 5.

Taking 2nd derivative

f''(x) =2

f''(5) = 2

As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5

The value can be found out by putting x=5 in the function

f(5) = (5)^2-10(5)+31\\=25-50+31\\=6

Hence,

<u>The function y = x 2 - 10x + 31 has a minimum  value of 6</u>

Hence,

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

8 0
3 years ago
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