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kodGreya [7K]
3 years ago
11

QI.

Mathematics
1 answer:
Marianna [84]3 years ago
6 0

What we're trying to do here is pairing elements of A with elements of B, and the rule for pairing them is that the least common multiple must be 2.

We can't use zeroes, because every multiple of 0 is still 0.

We can't either use numbers greater than 2, because their multiples will be greater than 2.

After this trimming, we're left with the following subsets:

\hat{A}=\{1,2\},\quad \hat{B}=\{1,2\}

So, the possible couples are:

(1,1),\quad (1,2),\quad (2,1),\quad (2,2)

The first couple is obviously not good, because the least common multiple of 1 and 1 is 1.

The other three are ok, because the least common multiple of 1 and 2 or 2 and 2 is 2.

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Answer:

The conclusion "T" logically follows from the premises given and the argument is valid

Step-by-step explanation:

Let us use notations to represent the steps

P: I take a bus

Q: I take the subway

R: I will be late for my appointment

S: I take a taxi

T: I will be broke

The given statement in symbolic form can be written as,

(P V Q) → R

S → (¬R ∧ T)

(¬Q ∧ ¬P) → S

¬R

___________________

∴ T

PROOF:

1. (¬Q ∧ ¬P) → S                Premise

2. S → (¬R ∧ T)                  Premise

3. (¬Q ∧ ¬P) → (¬R ∧ T)    (1), (2), Chain Rule

4. ¬(P ∨ Q) → (¬R ∧ T)      (3), DeMorgan's law

5. (P ∨ Q) → R                   Premise

6. ¬R                                 Premise

7. ¬(P ∨ Q)                        (5), (6), Modus Tollen's rule

8. ¬R ∧ T                          (4), (7), Modus Ponen's rule

9. T                                   (8), Rule of Conjunction

Therefore the conclusion "T" logically follows from the given premises and the argument is valid.

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Step-by-step explanation:?

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