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frosja888 [35]
3 years ago
6

What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)

Mathematics
1 answer:
dybincka [34]3 years ago
4 0

Answer:

amplitude; \frac{2}{3}

Phase shift; \pi units right

Period;\frac{2\pi}{3}

Step-by-step explanation:

The given function is

y=-\frac{2}{3}\cos(3t-3\pi)

This function is of the form;

y=A\sin (Bt+C)

The period is given by:

|A|=|-\frac{2}{3}|= \frac{2}{3}

The period is given by:

T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}

The phase shift is given by;

\frac{C}{B}=\frac{-\3pi}{3}=- \pi or \pi units right.

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2x = 2 × 2 = 4

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4 0
3 years ago
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8 0
3 years ago
What is three-fourths of 1,968
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I hope this helps! :_
7 0
3 years ago
Read 2 more answers
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