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Stolb23 [73]
3 years ago
15

Can someone help me with this math problem please ​

Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0

Bev is between the 6 and 8.  Bev is 7.  Jason is 5.  Mary is 4.  John is 8.

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A washing machine is filling up with water at a constant rate. The rate is Three-fourths of a gallon in StartFraction 1 over 5 E
konstantin123 [22]

Answer:

3/4 in 1/5 of 60 sec

1/5*60=12

3/4 in 12 seconds

3/4*5=15/4=3 3/4

He multiplied 3/4 by 1/5 instead of by its reciprocal , 5.

12/4=3

3 mph

3 0
3 years ago
Read 2 more answers
(-0.75x - 3) -(3.5x +8.4 )
Lostsunrise [7]

Answer:-27.15

Step-by-step explanation:........

6 0
3 years ago
Read 2 more answers
Check whether <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B5%7D%20" id="TexFormula1" title=" \frac{4}{5} " alt=" \f
steposvetlana [31]

Answer:

Non terminating

Step-by-step explanation:

4/5=0.8 so non terminating

Hope this helps :D

6 0
2 years ago
1. Choose the best descriptor for the graph of f(x)=e^x+5.
Black_prince [1.1K]

Starting from a parent function f(x), if you add a constant to the whole function, i.e. you perform the transformation

f(x) \to f(x)+k

you shift the graph of the parent function by k units, upwards if k is positive, downwards otherwise.

In this case, so, you're shifting, the graph of e^x 5 units upwards. Since the parent function passes through the point (0,1), because e^0=1, the shifted graph mantains the same x coordinate, but the y coordinate is increased by 5, because of the 5 units upwards shift.

3 0
3 years ago
If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,
S_A_V [24]
Taking y=y(x) and differentiating both sides with respect to x yields

\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

Solving for the first derivative, we have

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y

Differentiating again gives

\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

Solving for the second derivative, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}

Now, when x=1 and y=2, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63
3 0
3 years ago
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