Answer:
The code to this question can be given as:
Code:
int callsReceived,operatorsOnCall; //define variable as integer
Scanner ob= new Scanner(System.in);
//create object of scanner class for user input
System.out.println("Insert the value of callsReceived"); //print message.
callsReceived = ob.nextInt(); //input value.
System.out.println("Insert the value of operatorsOnCall"); //print message.
operatorsOnCall = ob.nextInt(); //input value.
if (operatorsOnCall == 0) //check number
{
System.out.println("INVALID"); //print message.
}
else
{
System.out.println(callsReceived/operatorsOnCall); //print value.
}
Explanation:
In the above code firstly we define 2 integer variable that name is already given in the question. Then we create the scanner class object for taking user input. Then we print the message for input first and second value from the user. then we use conditional statement. If the second variable that is operatorsOnCall is equal to 0. So It print INVALID. else it divide the value and print it.
Answer:
False ( A )
Explanation:
The implementation is incorrect hence the return would be false and this is because : root.left is supposed to be NULL, root.right is supposed to be NULL and when these conditions are met then the Binary tree would be empty.
The condition for the above statement would be represented as
if( root.left = = null && root.right == null &&root.info == null)
return true;
else
return false;
Answer:
Sandboxing.
Explanation:
SDLC or software development life cycle is a systematic approach to software development. It marks the birth and death of an application.
The application development starts from the research of the properties of the application to the design and development or implementation of the application.
After the implementation of the software, it is tested, comparing the design and the codes in the development process. The sandboxing testing process helps to isolate and test new lines of code added during the testing phase.
Answer:
$340
Explanation:
you have to multiply $400 bu 85% to get $340
If a robot is able to change its own trajectory as per the external conditions, then the robot is considered the intelligent option (A) is correct.
<h3>What is AI?</h3>
Unlike the natural intelligence exhibited by animals, including humans, artificial intelligence is a form of intelligence demonstrated by robots.
The question is incomplete.
The complete question is:
If a robot can alter its own trajectory in response to external conditions, it is considered to be:
A. intelligent
B. mobile
C. open loop
D. non-servo
E. None of the above
Robots are regarded as intelligent if they can alter their own course in response to environmental factors. These kinds of agents fall into the AI agent or Rational Agent group.
Thus, if a robot is able to change its own trajectory as per the external conditions, then the robot is considered the intelligent option (A) is correct.
Learn more about AI here:
brainly.com/question/27839745
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