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3 years ago

PLZ HELP ME! Directions up above the picture **MATH (Algebra)

Mathematics

1 answer:

Vikentia [17]3 years ago

6 0

Answer:

The answer to your question is t = 1.3 s

Step-by-step explanation:

Data

Equation h(t) = -4.9t² + v₀t + h₀

v₀ = 0 m/s

h₀ = 8 m

t = ?

h = 0 m

Process

1.- Substitute the values in the formula

0 = -4.9t² + 0t + 8

2.- Simplification

0 = -4.9t² + 8

3.- Solve for t

4.9t² = 8

t² = 8/4.9

t² = 1.63

4.- Result

t = 1.27 ≈ 1.3 s

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When a baseball is thrown upward, its height is a function of time. If this function is given by formula h(t)=−16t^2+24t+5, what

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Answer:

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3 years ago

Student to faculty is 17:3 The total is 740 how many students and faculty are at the college

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Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y= 740
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Since the total is 740, then X equal 740-111 =629.
The number of faculties is 111 and the number of students is 629.

7 0

3 years ago

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Hi help please! i’m struggling lol i already know the first part

sladkih [1.3K]

Answer:

180 Degrees minus 117= sixty three

answer is x is 63

Where did I get the 180?

- straight Angles have 180

- 117 is a part of 180

-so that is why you had to subtract

I hope this Helps You!!

7 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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3 years ago

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ale4655 [162]

Answer:

1st= 2 1/2

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Step-by-step explanation:

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3 years ago

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