Answer:
The upper limit of the 95% confidence interval is:
C.I_u = 200 + (58.8/)
Step-by-step explanation:
The formula is given as:
C.I = μ ± Z*σ/
The upper limit => C.I_u = μ + Z*σ/
The lower limit => C.I_l = μ - Z*σ/
The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.
The upper limit => C.I_u = 200 + 1.96*(30/)
= 200 + (1.96*30)/
= 200 + 58.8/
Answer:
We accept the null hypothesis, that is, that the mean weight of the cans is still of 12 ounces of fruit.
Step-by-step explanation:
Pineapple Corporation (PC) maintains that their cans have always contained an average of 12 ounces of fruit.
This means that the null hypothesis is:
The production group believes that the mean weight has changed.
This means that the alternate hypothesis is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
12 is tested at the null hypothesis:
This means that
They take a sample of 15 cans and find a sample mean of 12.05 ounces and a sample standard deviation of .08 ounces.
This means, respectibely, that
Value of the test statistic:
Pvalue of the test:
We are testing if the mean is different from a value, which means that the pvalue is 2 multiplied by 1 subtracted by the pvalue of z = 2.42.
Looking at the z-table, z = 2.42 has a pvalue of 0.9922
1 - 0.9922 = 0.0078
2*0.0078 = 0.0156
What conclusion can we make from the appropriate hypothesis test at the .01 level of significance?
0.0156 > 0.01. This means that at the 0.01 level, we accept the null hypothesis, that is, that the mean weight of the cans is still of 12 ounces of fruit.