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kap26 [50]
4 years ago
9

Find all the cube roots of 8​

Mathematics
2 answers:
PilotLPTM [1.2K]4 years ago
8 0

Answer:

2

Step-by-step explanation:

it's can be written as ^3√8 and taking it out is = 2

pshichka [43]4 years ago
4 0
The simple cube root of 8 is 2.

However, if you are looking for ALL :

The cube roots of 8 are 2, 2ω and 2ω2 where ω=−12+√32i is the primitive Complex cube root of 1. One way of finding these cube roots of 8 is to find all of the roots of x3−8=0.
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What Is The Missing Angle Measure of This Irregular Quadrilateral​
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4 years ago
Calculus 3 chapter 16​
o-na [289]

Evaluate \vec F at \vec r :

\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k

Compute the line element d\vec r :

d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt

Simplifying the integrand, we have

\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt

Then the line integral evaluates to

\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}

3 0
2 years ago
two sides of a triangle have lengths 6 and 17 which inequalities represent the possible lengths for the third side, x?
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Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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