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svetlana [45]
4 years ago
14

rearrange into quadratic form ax^2+bx+c=0. . 0.20= x^2/(25-x). . where a=1, and identify values of b and c

Mathematics
1 answer:
vivado [14]4 years ago
8 0
Simplifying 0.20 = x^2 / (25 - x):

Multiply both sides by (25 - x)
0.20(25 - x) = x^2

Distributing 0.20:
5 - 0.20x = x^2

Placing all equations on to one side:
x^2 + 0.20x - 5 = 0

Where:
a = 1
b = 0.20
c = -5


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Answer: The y-value of the vertex is

Step-by-step explanation: we know that

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where

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In this problem we have

-----> this a vertical parabola open upward

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient

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The y-value of the vertex is

5 0
2 years ago
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
HELP ME ASAP!!!! PLEASE HELP I AM DESPERATE!!!!!!!
evablogger [386]
First question
42 students

Second question 65%
5 0
4 years ago
Determine whether the triangles are similar by aa , ss , or sas ??
max2010maxim [7]

Answer:

1. AA

2. SSS

3. I´m not sure about this one, I´m sorry

4. Not similar

Step-by-step explanation:

This photo can help you identify!! I hope this helps

4 0
3 years ago
Anyone answering the coordinates subtraction can get there 100 points here.
Sholpan [36]

Answer:

c = -6

d = 2

Step-by-step explanation:

After reflection about the x-axis:

A --> A'

(x,y) --> (x,-y)

(2,3) --> (2,-3)

(4,3) --> (4,-3)

(2,6) --> (2,-6)

After translation:

(2 + c, -6 + d) --> (-4, -4)

2+c = -4

c = -6

-6+d = -4

d = 2

3 0
3 years ago
Read 2 more answers
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