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Phantasy [73]
2 years ago
10

Solve the inequality for x. -24 > x +4

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
3 0

Step-by-step explanation:

- 24 > x + 4

- 28 > x

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Can someone help me? I figured out part B however, I am struggling with part A and I would be so happy if any of you helped me.
UkoKoshka [18]
<h3>Answer:  262,785</h3>

Note: you may need to delete the comma

============================================================

Explanation:

The info "5 months" is never used to compute the mean. We could easily replace it with "6 months" or "7 months" or any stretch of time, and still get the same answer. So we'll ignore this value.

What we'll do is add up the 21 items given to us, and then divide by 21.

Because there are so many values, and it's easy to get lost, I'm going to add up across the rows

  • Row One: 256,229+253,657+218,747+246,163+235,626+288,694 = 1,499,116
  • Row Two: 316,265+196,721+319,620+285,077+215,152+253,291 = 1,586,126
  • Row Three: 315,011+199,901+265,443+291,806+303,556+215,359 = 159,1076
  • Row Four: 258,554+293,658+289,935 = 842,147

Those subtotals then add up to this

1,499,116+1,586,126+1,591,076+842,147 = 5,518,465

This is the same as adding up all 21 values.

Finally, we divide that sum over 21 as there are 21 values in this list

(5,518,465)/21 = 262,784.047619048

That value then rounds up to 262,785

If your teacher just wanted things to the nearest whole number (without rounding up), then the answer would be 262,784

Side note: using a spreadsheet program would probably be the most efficient/fastest method for this type of problem.

3 0
2 years ago
the width of a rectangle is 3 units less than the length. if the area is 130 square units, then find the dimensions of the recta
Basile [38]

Answer:

Length = 10

Width = 13

Step-by-step explanation:

If the width of a rectangle is 3 units less than the length and if the area is 130 square units, the length is 10 units and the width is 13 units.

Formula: A=wl

Therefore, you have to find what two numbers multiply together in order to recieve 130 units.

A=wl=13·10=130

4 0
3 years ago
Read 2 more answers
A lighthouse casts a shadow 32 meters long at the same time a nearby statue casts a shadow that is 9 meters long. If the statue
Pavlova-9 [17]

Answer:

40

Step-by-step explanation:

Ok, so basically let's start with a proportion.

x/32 = 11.25/9

Cross multiply:

x * 9 = 32 * 11.25

9x = 32 * 11.25

9x = 360

Solving for variable 'x'.

Divide each side by '9'.

x = 40

I don't know if this is the correct answer, but it was based on my math. I hope this helps!

5 0
3 years ago
Can someone help with this?
matrenka [14]

Answer:

i wanna say -80?

Step-by-step explanation: so when you go from -8 to -11 its counts by 3 -11 to -14 its 3 so count up to get our answer.   i just seen how many was in each 5 set which was 12 so i did -20 -12 so then i just added up and got -80

5 0
2 years ago
In a​ study, 36​% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop
steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36​% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this​ area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly​ selected, 3 or fewer are in excellent health.

i.e. P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)

Formula :P(x=r)=^nC_r p^r q ^ {n-r}

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)

P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}

P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!}  (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}

P(x\leq 3)=0.390748

Hence  the probability that when 11 adults are randomly​ selected, 3 or fewer are in excellent health is 0.3907

5 0
3 years ago
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