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antiseptic1488 [7]

2 years ago

11

Find the measures of the angles marked x and y. remember that (1) the sum of the measures of the angles of a triangle is 180 de

grees 180°, (2) supplementary angles have a sum of 180 degrees 180°

1 answer:

Sergio039 [100]2 years ago

6 0

Is there supposed to be a picture because I dont see the angles?

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Is 5.421 greater or less then 5.4

zavuch27 [327]

Greater than 5.4 i hate the 20 characters rule

5 0

2 years ago

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Serhud [2]

Answer:

Step-by-step explanation:

12.9 + 10.2x = 35.1

10.2x = 35.1 - 12.9

10.2x = 22.2

x = 22.2/10.2

x= 222/102 = 111/51

$x= 2\dfrac{9}{51}$

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2 years ago

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Solve for bbb.<br> -3b+2.5 = 4−3b+2.5=4

Anna11 [10]

The answer is not possible because both most common factors cancel each other out

7 0

2 years ago

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Pencils that were selling at three for 25 cents are now on sale at five for 29 cents. How much money, in cents, would you save b

natita [175]

Answer:

We would save $1.52 cents

Step-by-step explanation:

3 the pencil were at sale for 25 cent

1 pencil = 25 cent/3 =8.33 cent per one pencil

5 the pencil were at sale for 29 cent

1 pencil = 29 cent/5 =5.8 cent per one pencil

If we bought 60 pencil in group of 3 for 25 cent

=60/3= 20 pencil

25cents * 20 pencil = 500 cent per 60 pencil

If we bought 60 pencil in group of 5 for 29 cent

=60/5= 12 pencil

29cents * 12 pencil = 348 cent per 60 pencil

From the analysis, the 5 pencil for 29 cent is cheaper are we are going to save: 500-348= 152 cents

7 0

2 years ago

Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.

Levart [38]

Answer:

The standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Step-by-step explanation:

We know that:

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

$x^2\:+\:10x\:+\:6y\:=\:47$

Rewriting the equation in the standard form

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

where

vertex (h, k) = (-5, 12)

7 0

1 year ago