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Shalnov [3]
2 years ago
15

the revenue from selling x shirts is r(x)=12. the cost of buying x shirts is c(x)=5x+20. the profit from selling x shirts is p(x

)=r(x) - c(x). what is p(x)?
Mathematics
2 answers:
Olegator [25]2 years ago
7 0

Answer:

The value of p(x)=-5x-8

Step-by-step explanation:

Given : The revenue from selling x shirts is r(x)=12. The cost of buying x shirts is c(x)=5x+20. The profit from selling x shirts is p(x)=r(x) - c(x).

To find : What is p(x)?

Solution :

The revenue from selling x shirts is r(x)=12.

The cost of buying x shirts is c(x)=5x+20.

The profit from selling x shirts is p(x)=r(x) -c(x)

Substitute the values in the formula,

p(x)=12 -(5x+20)

p(x)=12 -5x-20

p(x)=-5x-8

Therefore, The value of p(x)=-5x-8

BabaBlast [244]2 years ago
3 0

Answer:

The profit function would be p(x) = 7x - 20

Step-by-step explanation:

In order to find this, start by listing just as asked.

p(x) = r(x) - c(x)

Now input the functions where indicated

p(x) = 12x - (5x + 20)

p(x) = 12x - 5x - 20

p(x) = 7x - 20

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algol13
Answer: 12
6x2 is 12 and 12x3 is 38.
We will first find the prime factorization of 12 and 36. After we will calculate the factors of 12 and 36 and find the biggest common factor number .

3 0
3 years ago
The area of the parallelogram shown is (35x2 + 46x +15) square meters. If its base is (5x + 3) meters, find
attashe74 [19]

Answer:

(7x + 5)m

Step-by-step explanation:

area = base  * height = (35x2 + 46x +15) m²

base = (5x + 3)

Using algebraic division, find the height. SEE ATTACHMENT

height = (7x + 5)

7 0
2 years ago
A second grade student is 4 feet tall. Her teacher is 5 2/3 feet tall. How many times as tall as the student is the teacher
Alchen [17]

Answer:

The teacher is 1.416667 times taller than the student

Step-by-step explanation:

(5 2/3)/4

=1.416667

4 0
2 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
2 years ago
Someone plzzzzzz!!!!!
Alex777 [14]

Answer:

yes

Step-by-step explanation:

5 0
3 years ago
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