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3 years ago

the area of a rectangular field is 8148 yards squared if the width of the field is 84 yards what is its length

Mathematics

1 answer:

poizon [28]3 years ago

3 0

The area of a rectangle is the product of its dimensions:

$A = w \cdot l$

where w and l are width and length, respectively. So, if we plug your values, we have

$8148 = 84l$

So, if you divide both sides by 84, you have

$l = \dfrac{8148}{84} = 97$

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a leaf hangs from a branch 12 feet in the air. it falls to the ground at a rate of 0.25 feet per second. which graph could repre

Kipish [7]

For this case we have an equation of the form:
$h (t) = (1/2) * (a) * (t ^ 2) + v0 * t + h0
$
Where,
h0: initial height
v0: initial speed
a: acceleration
Substituting values we have:
$h (t) = (1/2) * (- 32) * (t ^ 2) + 0.25 * t + 12
$
Rewriting we have:
$h (t) = -16t ^ 2 + 0.25 * t + 12
$
Note: see attached image
Answer:
$h (t) = -16t ^ 2 + 0.25 * t + 12$

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2 years ago

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Mazyrski [523]

Answer:

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3 years ago

Simplify the expression using properties of operations. (−r−5)−(−2r−4)

Pachacha [2.7K]

Answer:r-1

Step-by-step explanation:

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-r+-5+2r+4. -r-5+2r+4

r-1 r-1

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3 years ago

A survey showed that 77% of us need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. 13 adults are randomly

earnstyle [38]

Using the binomial distribution, it is found that the probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

For each person, there are only two possible outcomes, either they need correction for their eyesight, or they do not. The probability of a person needing correction is independent of any other person, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

A survey showed that 77% of us need correction, hence p = 0.77.

13 adults are randomly selected, hence n = 13.

The probability that at least 12 of them need correction for their eyesight is given by:

$P(X \geq 12) = P(X = 12) + P(X = 13)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{13,12}.(0.77)^{12}.(0.23)^{1} = 0.1299$

$P(X = 13) = C_{13,13}.(0.77)^{13}.(0.23)^{0} = 0.0334$

Then:

$P(X \geq 12) = P(X = 12) + P(X = 13) = 0.1299 + 0.0334 = 0.163$

The probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

More can be learned about the binomial distribution at brainly.com/question/24863377

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