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Snezhnost [94]
3 years ago
9

Let f(x)=x2−2x−4 . What is the average rate of change for the quadratic function from x=−1 to x = 4?

Mathematics
2 answers:
elena55 [62]3 years ago
7 0
The average rate of change <span>x=−1 to x = 4 is 

A= f(4) -f(-1) / 4- (-1)
f(4)=4²-2x4-4=16-12=4
f(-1)=1+2-4= -1
</span><span>f(4) -f(-1) / 4- (-1) = 4-(-1)/4-(-1)= 5/5=1
</span>the rate of change is A=1
goblinko [34]3 years ago
4 0

Answer:

The average rate of change for f(x) from x=−1 to x = 4 is, 1

Step-by-step explanation:

Average rate A(x) of change for a function f(x) over [a, b] is given by:

A(x) = \frac{f(b)-f(a)}{b-a}

As per the statement:

f(x) = x^2-2x-4

we have to find the average rate of change from x = -1 to x = 4

At x = -1

f(-1) = (-1)^2-2(-1)-4 = 1+2-4 = -1

and

at x = 4

f(4) = (4)^2-2(4)-4 = 16-8-4 = 4

Substitute these in [1] we have;

A(x) = \frac{f(4)-f(-1)}{4-(-1)}

⇒A(x) = \frac{4-(-1)}{4+1}

⇒A(x) = \frac{5}{5}

Simplify:

A(x) = 1

Therefore, the average rate of change for f(x) from x=−1 to x = 4 is, 1

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