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Genrish500 [490]
2 years ago
12

Lauren eats 1/8 of a chocolate cake before supper, and then eats another 1/8 after supper.

Mathematics
1 answer:
Sav [38]2 years ago
8 0

Answer:

she ate 2/8ths and left 6/8ths

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What is the midpoint of the segment shown below?
d1i1m1o1n [39]

Answer:

A

Step-by-step explanation:

Calculate the midpoint using the midpoint formula

[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

with (x₁, y₁ ) = (- 1, 5) and (x₂, y₂ ) = (5, 5)

midpoint = [ 0.5(- 1 + 5), 0.5(5 + 5) ]

              = [ 0.5(4), 0.5(10) ] = (2, 5 ) → A

3 0
3 years ago
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25% is equivalent to what fraction in reduced terms
marishachu [46]
The solution is 1/4 because 25/100 / 25/25 1/4

8 0
3 years ago
The surface areas of the two solids shown above are equal.<br> O A. True<br> O B. False
nikdorinn [45]

Answer:

False

Step-by-step explanation:

If we were to flip the solid on the left so its parallel to the solid on the right, we would be able to compare the two more easier.

We can see that the right solid has dimensions of:

L = 1 cm

W = 3 cm

H = 5 cm

The left solid has dimensions of:

L = 1

W = 2

H = 7

If we were to add these all up, they would not equal.

R: 1 + 3 + 5 = 9

L: 1 + 2 + 7 = 10

3 0
3 years ago
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Need help on these math questions. please and thank u
Svetach [21]

9514 1404 393

Answer:

  a) x = -3

  b) y = (28/27)x -27

Step-by-step explanation:

a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...

  x = constant

For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...

  x = -3

__

b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...

  m = -1/(-27/28) = 28/27

Using the point-slope equation for a line, we can model Ace Rd as ...

  y -y1 = m(x -x1)

  y -1 = (28/27)(x -27)

  y = (28/27)x -27

4 0
3 years ago
Can sum1 help me with this asap pls :)
IrinaVladis [17]
5 units (extra characters......)
8 0
3 years ago
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