There is a not so well-known theorem that solves this problem.
The theorem is stated as follows:
"Each angle bisector of a triangle divides the opposite side into segments proportional in length to the adjacent sides" (Coxeter & Greitzer)
This means that for a triangle ABC, where angle A has a bisector AD such that D is on the side BC, then
BD/DC=AB/AC
Here either
BD/DC=6/5=AB/AC, where AB=6.9,
then we solve for AC=AB*5/6=5.75,
or
BD/DC=6/5=AB/AC, where AC=6.9,
then we solve for AB=AC*6/5=8.28
Hence, the longest and shortest possible lengths of the third side are
8.28 and 5.75 units respectively.
Answer:
720
Step-by-step explanation:
I will use the following counting principle:
Product rule: if there are n ways of doing something, and m ways of doing another thing, there are n×m ways of doing both things.
First, we have to choose the 3 people that will be in the first row. This is a 3-element subset of the set of six people, therefore there are
ways of doing this.
Now, we have to arrange the order of the 2 lrows. Each one has 3 people, so there are 3!=6 ways to form one rows. Hence, there are 3!²=36 ways of arranging the two rows.
By the product rule, there are 20×36=720 ways of arrange the officers.
Answer:
area= 7/8×8/5 = 7/5 =1.4 sq feet