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saw5 [17]
3 years ago
5

Please help me with this problem ASAP

Mathematics
1 answer:
oee [108]3 years ago
8 0

Answer:

Step-by-step explanation:

I think it's 64

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What is 200/30 in a mixed number
mixer [17]
6 20/30

hope it helps
7 0
3 years ago
I need the answer for (y 7)4 8-5y
Neko [114]
Answer is:<span>
= <span><span>48<span>y7 -</span></span> <span>5<span>y.</span></span></span></span>
8 0
3 years ago
What is the solution to the equation 2 (x-3) ^2 =13 help help ASAP !
olganol [36]

Answer:

3+sqrt(13/2)

3-sqrt(13/2)

Step-by-step explanation:

2 (x-3) ^2 =13

Divide each side by 2

2/2 (x-3) ^2 =13/2

(x-3) ^2 =13/2

Take the square root of each side

sqrt((x-3) ^2) =±sqrt(13/2)

x-3 = ±sqrt(13/2)

Add 3 to each side

x-3+3 = 3±sqrt(13/2)

x = 3±sqrt(13/2)

4 0
3 years ago
Read 2 more answers
If the product of six tenths and three tenths is subtracted from the sum of two tenths and four tenths, what
MakcuM [25]

Answer:

-\frac{1}{200}

Step-by-step explanation:

\frac{6}{10}×\frac{3}{10}-\frac{2}{10}+\frac{4}{10}

\frac{6}{10}×\frac{3}{10}=\frac{18}{100}

\frac{18}{100}-\frac{2}{10}=-\frac{1}{50}

-\frac{1}{50}+\frac{4}{10}=\frac{1}{200}

5 0
3 years ago
If U-235 has a half-life of 713 million years and the age of the sample is 2.631 billion years old then how many half-lifes has
lutik1710 [3]
<span>As the age of the U-235 sample is 2.631 billion years, and the half-life of U-235 is 713 million years, the sample has undergone 2.361 X 1,000,000,000 / 713 X 1,000,000 = 3.69 half lives. In each half-life the sample reduces to half its original weight according to the radioactive Half-Life Formula: ln (Nt /N0) = -kt, where N0 = mass of the original weight of radioactive material, Nt = mass of radioactive material at time t, k = decay constant and t = time interval . We have to put Nt/N0 = 1/2 for time interval = half-life.</span>
8 0
3 years ago
Read 2 more answers
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