Answer:
Equation of a line, y = mx+c
Slope (m)= (Y2-Y1)/(X2-X1), let Y2=7, Y1=3 , X2=2 and X1=1
m=(7-3)/(2-1)
= 4/1
= 4
Picking any value of y and its corresponding x including m, put them into the equation of the line
y=mx+c
3 =4(1)+c
3=4+c
3-4=c
-1=c
y=mx+c
y=4x+(-1)
y=4x-1
Answer:
B, using a sample of size 200
Step-by-step explanation:
just got it right
We will translate the given statement in the problem into
x + y = 90
x - y = 90 - 86 = 4 where x and y are the angles that are complementary. solving simultaneously, x = 47 degreesy = 43 degrees.
Let the equation be:
y = ax^2 + bx + c.
Then, substitue the three points into the equation.
First point: 0 = a0^2 + b0 + c.
So c = 0.
Second point: -2 = a(-1)^2 + b(-1) + c.
So a - b + c = -2.
Third point: 6 = a*1^2 + b*1 + c.
So a + b + c = 6.
We know that c=0 already, so we substitute c=0 into the last two equations and we would get:
a - b = -2
a + b = 6
We add the two equations and we get:
2a = 4
a = 2
Then, we substitute a=2 into a-b=-2 and we get:
-b = -4
b = 4
Now we know a = 2, b = 4, and c = 0
Then, the equation of the parabola would be:
2x^2 + 4x
