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salantis [7]
3 years ago
10

Olivia wants to add buttons and clickable features to her website. Which language should she use?

Computers and Technology
2 answers:
Feliz [49]3 years ago
8 0

B. HTML. I hope this helps!!!

Nikitich [7]3 years ago
4 0

The answer is B) HTML  hope this helps!!!!!!!!!!!!!!!

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There are two kinds of emotions: positive and negative. True False
fgiga [73]

Answer:

False

Explanation:

There are many emotions the human brain can experience

6 0
2 years ago
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The answer is family and friends
nadya68 [22]
Family and Friends



you said the answer was that, soooooo
5 0
3 years ago
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Write a function int checkBalance(char exp[]); that can take an expression as input and check whether the parenthesis used in th
mylen [45]

Answer:

Explanation:

The following code is written in Java. It uses for loops to loop through the array of characters, and uses IF statements to check if the symbols in the expression are balanced. If so it returns true, otherwise it breaks the function and returns false. Two test cases have been provided in the main method and the output can be seen in the attached image below.

import java.util.ArrayList;

class Brainly {

   public static void main(String[] args) {

       char[] exp = { '[', 'A', '*', '{', 'B', '(', 'C', 'D', ')', '}', ']'};

       char[] exp2 = {'[', 'A', '*', '(', 'C', '}', ']'};

       System.out.println(checkBalance(exp));

       System.out.println(checkBalance(exp2));

   }

   public static boolean checkBalance(char exp[]) {

       ArrayList<Character> symbols = new ArrayList<>();

       for (char x: exp) {

           if ((x =='[') || (x == '{') || (x == '(')) {

               symbols.add(x);

           }

           if (x ==']') {

               if (symbols.get(symbols.size()-1) == '[') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

           if (x =='}') {

               if (symbols.get(symbols.size()-1) == '{') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

           if (x ==')') {

               if (symbols.get(symbols.size()-1) == '(') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

       }

       return true;

   }

}

3 0
3 years ago
What are the contents of memory locations 200, 201, 202, and 203 if the word 1234 is stored at offset 200 and the word 5678 is s
Igoryamba

Answer:

Data at the following addresses will be as following:-

200 :- 34

201 :- 12

202 :- 78

203 :- 56

Explanation:

If there is 1 byte storage.

if the data is of 4 digits.Then we have to store it in 2 memory locations.

The first two digits will be stored at the higher byte address that is 201 and the last two digits will be stored at then lower byte address that is 200.

The case is same with the next data 5678.

At address 202 :- 78 will be stored and at address 203 :- 56 will be stored.

3 0
3 years ago
Randomly choose rock, paper, or scissors for the computer
Pepsi [2]

import random

computer_choice = random.choice(["rock", "paper", "scissors"])

user_choice = input("rock, paper, or scissors? ")

if computer_choice == user_choice:

   print("It's a draw!")

elif user_choice == "rock" and computer_choice == "scissors":

   print("You win!")

elif user_choice == "paper" and computer_choice == "rock":

   print("You win!")

elif user_choice == "scissors" and computer_choice == "paper":

   print("You win!")

else:

   print("The computer wins!")

I wrote my code in python 3.8. I hope this helps.

8 0
3 years ago
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